合并 2 个查询并在列中返回一个结果

Question

抱歉，如果这个问题已经得到解答，我查看了但找不到我正在寻找的确切内容。我有 2 组查询

• 查询 1：借记通知单查询我想为每个 Account_number 返回 1 个借记通知单（没有具体的偏好）
• 查询 2：贷项通知单查询我想为每个 Account_number 返回 1 个贷项通知单（没有具体的偏好），匹配查询 1 和 2 按账号并在列而不是行中显示结果。

第一个问题：我需要从查询 1 中限制每个帐户的借方通知单和从查询 2 中的每个帐户的贷方通知单。然后通过帐号匹配查询 1 和查询 2，并在列中返回结果。所需的结果显示在下面的屏幕截图中。

查询 #1 借记通知单查询：

Select distinct 
    hca.account_number, hcsu.attribute8, hcsu.attribute9,
    apsa.amount_due_remaining debit_memo_amount, apsa.customer_trx_id, rcta.trx_number
from 
    hz_cust_accounts hca, hz_cust_acct_sites_all hcas, hz_cust_site_uses_all hcsu, ra_customer_trx_all rcta, ar_payment_schedules_all apsa, manar.man_om_consignments mac
where 
    1 = 1
    and hca.cust_account_id = hcas.cust_account_id
    and hca.cust_account_id = rcta.bill_to_customer_id
    and rcta.customer_trx_id = apsa.customer_trx_id
    and hcas.cust_acct_site_id = hcsu.cust_acct_site_id
    and hcsu.SITE_USE_CODE = 'BILL_TO'
    and hcsu.status = 'A'
    and ((apsa.amount_due_remaining > 0 and hcsu.attribute9 = 'CUSTOMER REFUND'))
    and mac.CONSIGNMENT_ID = rcta.attribute2
order by 2, 1, 5;

查询 #2 贷项凭单查询：

Select distinct 
    hca.account_number, hcsu.attribute8, hcsu.attribute9,
    apsa.amount_due_remaining credit_memo_amount, apsa.customer_trx_id, rcta.trx_number
from 
    hz_cust_accounts hca, hz_cust_acct_sites_all hcas, hz_cust_site_uses_all hcsu, ra_customer_trx_all rcta, ar_payment_schedules_all apsa, manar.man_om_consignments mac
where 
    1 = 1
    and hca.cust_account_id = hcas.cust_account_id
    and hca.cust_account_id = rcta.bill_to_customer_id
    and rcta.customer_trx_id = apsa.customer_trx_id
    and hcas.cust_acct_site_id = hcsu.cust_acct_site_id
    and hcsu.SITE_USE_CODE = 'BILL_TO'
    and hcsu.status = 'A'
    and ((apsa.amount_due_remaining < 0 and  hcsu.attribute9= 'CUSTOMER REFUND'))
    and mac.CONSIGNMENT_ID = rcta.attribute2
order by 
    2, 1 , 5;

想要的结果：

Answer 1

这不是一个解决方案，而且评论时间太长。为什么不从客户 a/c#12000033 或任何您知道有贷项通知单的客户帐号开始，并在此过程中向后工作和调整。

 with credit as ( Select distinct hca.account_number,hcsu.attribute8,hcsu.attribute9,apsa.amount_due_remaining,apsa.customer_trx_id, rcta.trx_number
        from hz_cust_accounts hca, hz_cust_acct_sites_all hcas, hz_cust_site_uses_all hcsu, ra_customer_trx_all rcta, ar_payment_schedules_all apsa, manar.man_om_consignments mac
        where 1=1
        and hca.cust_account_id = hcas.cust_account_id
        and hca.cust_account_id = rcta.bill_to_customer_id
        and rcta.customer_trx_id = apsa.customer_trx_id
        and hcas.cust_acct_site_id = hcsu.cust_acct_site_id
        and hcsu.SITE_USE_CODE = 'BILL_TO'
        and hcsu.status = 'A'
        and((apsa.amount_due_remaining < 0 and  hcsu.attribute9= 'CUSTOMER REFUND') )
        and mac.CONSIGNMENT_ID = rcta.attribute2
        and hca.account_number= 12000033
        order by 2, 1 , 5),
    debit as (
    Select distinct hca.account_number,hcsu.attribute8,hcsu.attribute9,apsa.amount_due_remaining,apsa.customer_trx_id, rcta.trx_number
    from hz_cust_accounts hca, hz_cust_acct_sites_all hcas, hz_cust_site_uses_all hcsu, ra_customer_trx_all rcta, ar_payment_schedules_all apsa, manar.man_om_consignments mac
    where 1=1
    and hca.cust_account_id = hcas.cust_account_id
    and hca.cust_account_id = rcta.bill_to_customer_id
    and rcta.customer_trx_id = apsa.customer_trx_id
    and hcas.cust_acct_site_id = hcsu.cust_acct_site_id
    and hcsu.SITE_USE_CODE = 'BILL_TO'
    and hcsu.status = 'A'
    and((apsa.amount_due_remaining > 0 and  hcsu.attribute9= 'CUSTOMER REFUND') )
    and mac.CONSIGNMENT_ID = rcta.attribute2
    and hca.account_number= 12000033
    order by 2, 1 , 5)

    select a.*,b.* from  credit a  -- remove unnecessary columns later
    join debit b
    on (a.account_number=b.account_number)
    and (a.amount_due_remaining+b.amount_due_remaining)=0   -- find matching reverse entry