【发布时间】:2018-11-20 11:38:04
【问题描述】:
我正在尝试获取具有 16 色位图的图像。
我在互联网帖子上找不到解决方案。
这里是简单的实现。
#include "stdafx.h"
#include <windows.h>
#include <stdio.h>
LPBITMAPINFO ConstructBitmapInfo(int nBits, int nX, int nY);
VOID RocketBuffer(LPVOID lpData);
int _tmain(int argc, _TCHAR* argv[])
{
HWND hDesktop = NULL;
HDC hCurrenDC = NULL;
INT nX, nY;
LPBITMAPINFO lpBmpInfo;
HBITMAP hBmpScreen;
LPVOID lpBmpBuffer = NULL;
if(NULL == (hDesktop = GetDesktopWindow()))
return GetLastError();
if (NULL == (hCurrenDC = GetDC(hDesktop)))
return GetLastError();
nX = GetSystemMetrics(SM_CXSCREEN);
nY = GetSystemMetrics(SM_CYSCREEN);
HDC hOrgMemDC = NULL;
hOrgMemDC = CreateCompatibleDC(hCurrenDC);
lpBmpInfo = ConstructBitmapInfo(4, nX, nY);
hBmpScreen = CreateDIBSection(hCurrenDC, lpBmpInfo, DIB_RGB_COLORS, &lpBmpBuffer, NULL, 0);
SelectObject(hOrgMemDC, hBmpScreen);
if(!BitBlt(hOrgMemDC, 0, 0, nX, nY, hCurrenDC, 0, 0, SRCCOPY))
{
return GetLastError();
}
LPBYTE lpWriteData = new BYTE[lpBmpInfo->bmiHeader.biSizeImage * 2];
memcpy(lpWriteData, lpBmpBuffer, lpBmpInfo->bmiHeader.biSizeImage);
RocketBuffer(lpBmpBuffer);
delete[] lpWriteData;
return 0;
}
LPBITMAPINFO ConstructBitmapInfo(int nBits, int nX, int nY)
{
int color_num = nBits <= 8 ? 1 << nBits : 0;
int nBISize = sizeof(BITMAPINFOHEADER) + (color_num * sizeof(RGBQUAD));
BITMAPINFO *lpbmi = (BITMAPINFO *) new BYTE[nBISize];
BITMAPINFOHEADER *lpbmih = &(lpbmi->bmiHeader);
lpbmih->biSize = sizeof(BITMAPINFOHEADER);
lpbmih->biWidth = nX;
lpbmih->biHeight = nY;
lpbmih->biPlanes = 1;
lpbmih->biBitCount = nBits;
lpbmih->biCompression = BI_RGB;
lpbmih->biXPelsPerMeter = 0;
lpbmih->biYPelsPerMeter = 0;
lpbmih->biClrUsed = 0;
lpbmih->biClrImportant = 0;
lpbmih->biSizeImage = (((lpbmih->biWidth * lpbmih->biBitCount + 31) & ~31) >> 3) * lpbmih->biHeight;
if (nBits >= 16)
return lpbmi;
HDC hDC = GetDC(NULL);
HBITMAP hBmp = CreateCompatibleBitmap(hDC, 1, 1);
GetDIBits(hDC, hBmp, 0, 0, NULL, lpbmi, DIB_RGB_COLORS);
ReleaseDC(NULL, hDC);
DeleteObject(hBmp);
return lpbmi;
}
VOID RocketBuffer(LPVOID lpData)
{
// ...
}
我无法将lpWriteData 输出为* .bmp 文件。这不是 BMP 格式。
因此,函数RocketBuffer (LPVOID lpData) 将无法正确执行其功能。
问题是如何使用 16 色位图在内存中获取屏幕截图输出。
【问题讨论】:
-
使用
Gdiplus和CLSID将图像保存为位图。 -
@A.Godnov 谢谢,但我想操作屏幕截图缓冲区。如果我按照你的方式做,我该怎么办?
标签: c++ image winapi screenshot