Python "for loop and def" 练习并得到 "TypeError: 'int' object is not iterable"

Question

这是我的编码如下。

import random

import math

def count_hit_in_cirle(iteration):

    randX=random.uniform(-1.0,1.0) # returns a X random float in INclusive [-1.0, 1.0]
    randY=random.uniform(-1.0,1.0) # returns a y random float in INclusive [-1.0, 1.0]
    one_if_in_circle=0
    for i in range(iteration):
         def one_if_in_circle(randX, randY):
             if math.sqrt(randX*randX+randY*randY) <= 1:
                 return 1
             else:
                 return 0
    return (sum(one_if_in_circle(randX, randY)))

count_hit_in_cirle(1000)

但是我得到了这样的错误：

count_hit_in_cirle(1000)
Traceback (most recent call last):

  File "<ipython-input-4-4dcc579bc645>", line 1, in <module>
    count_hit_in_cirle(1000)

  File "<ipython-input-3-4fbc77f1c9ec>", line 11, in count_hit_in_cirle
    return (sum(one_if_in_circle(randX, randY)))

TypeError: 'int' object is not iterable

然后我尝试了：

return (sum(one_if_in_circle(randX, randY)))

我还是有错误：

"TypeError: 'function' 对象不可迭代"

有没有人可以告诉我如何修复我的编码？非常感谢

Answer 1

您似乎正在尝试创建一个生成器。您需要将循环放在函数内部，而不是围绕它，并使用yield 而不是return。

def count_hit_in_cirle(iteration):

    randX=random.uniform(-1.0,1.0) # returns a X random float in INclusive [-1.0, 1.0]
    randY=random.uniform(-1.0,1.0) # returns a y random float in INclusive [-1.0, 1.0]
    one_if_in_circle=0
    def one_if_in_circle(randX, randY):
        for i in range(iteration):
            if math.sqrt(randX*randX+randY*randY) <= 1:
                yield 1
            else:
                yield 0
    return (sum(one_if_in_circle(randX, randY)))

您的函数只返回一个整数，而不是 sum() 可以迭代的序列。

Answer 2

one_if_in_circle 在one_if_in_circle=0 中定义为int 类型变量，在def one_if_in_circle(randX, randY) 中定义为函数。换一个。