在oracle中将列转换为行[重复]答案

【问题标题】：Convert columns to rows in oracle [duplicate]在oracle中将列转换为行[重复]
【发布时间】：2014-01-27 13:34:02
【问题描述】：

这是我在 oracle 11g 中的表：

**date          qty1            qty2             qty3           qty4**
2-Feb-14            61           64             52           54
2-Mar-14           124          130            149          156

我想把它转换成下表。即在日期上加上 7 天并转置数量。我有 qty52 这样的指标

***date        qty***
**2-Feb-14        61**
9-Feb-14          64
16-Feb-14         52
23-Feb-14         54
**2-Mar-14        124**
9-Mar-14          130
16-Mar-14         149
23-Mar-14         156

【问题讨论】：

标签： oracle oracle11g oracle10g oracle-sqldeveloper

【解决方案1】：

试一试：

WITH t(my_date, val, val2, val3, val4)
AS ( 
SELECT to_date('01/01/2014 12:00:00 AM', 'dd/mm/yyyy hh:mi:ss am'), 1,2,3,4 from dual
UNION ALL
SELECT to_date('01/02/2014 12:00:00 AM', 'dd/mm/yyyy hh:mi:ss am'), 5,6,7,8 FROM dual
)
SELECT (my_date-7) + (row_number() OVER (partition by my_date ORDER BY my_date)*7)  my_date, value as qty
FROM (
     ( SELECT my_date, val, val2, val3, val4 FROM t
     ) unpivot ( value FOR value_type IN (val, val2, val3, val4) ) );

输出：

MY_DATE                        QTY
----------------------- ----------
01/01/2014 12:00:00 AM           1 
08/01/2014 12:00:00 AM           2 
15/01/2014 12:00:00 AM           3 
22/01/2014 12:00:00 AM           4 
01/02/2014 12:00:00 AM           5 
08/02/2014 12:00:00 AM           6 
15/02/2014 12:00:00 AM           7 
22/02/2014 12:00:00 AM           8

【讨论】：

【解决方案2】：

select date,qty from
(select date,qty1 as qty
from tbl
union
select date+7 as date,qty2 as qty
from tbl
union
select date+14 as date,qty3 as qty
from tbl
union
select date+21 as date,qty4 as qty
from tbl)
order by date

【讨论】：

谢谢你们！！所有的建议都有效！！

【解决方案3】：

如果您有 Oracle 11g，我会考虑使用 UNPIVOT 来实现。

select
  start_date + to_number(week_number) * 7,
qty
from (
  select *
  from quantity_data 
  unpivot (qty for week_number 
           in (qty1 as '0', qty2 as '1', qty3 as '2', qty4 as '3')) 
)

这是 ajmalmhd04 示例的替代方法，使用 to_number 代替 row_number 分析函数。不过，ajmalmhd04 的答案可能更通用

如果您还没有 Oracle 11g，那么试试这个选项：

with pivot_data as (
  select 0 as pivot_col from dual union all
  select 1 from dual union all
  select 2 from dual union all
  select 3 from dual
)
select 
  start_date + (7 * pivot_col) as start_date,
  case 
    when pivot_col = 0 then qty1
    when pivot_col = 1 then qty2
    when pivot_col = 2 then qty3
    when pivot_col = 3 then qty4 end as qty
from 
  quantity_data cross join pivot_data
order by 1

【讨论】：

【解决方案4】：

试试这个

with tab(date_d,qty1,qty2,qty3,qty4) as (
   select '2-Feb-14',61,64,52,54 from dual union all
   select '2-Mar-14',124,130,149,156 from dual),
tab2(dd, ss) as (select date_d, qty1||','||qty2||','||qty3||','||qty4  from tab)
select to_date(dd) + ((level-1) * 7) "DATE", regexp_substr(ss, '[^(,)]+', 1, level) "QTY"
  from tab2
connect by level <= length(ss) - length(replace(ss, ',')) + 1
  and prior ss = ss
  and prior sys_guid() is not null

输出

|                            DATE | QTY |
|---------------------------------|-----|
|    March, 02 2014 00:00:00+0000 | 124 |
|    March, 09 2014 00:00:00+0000 | 130 |
|    March, 16 2014 00:00:00+0000 | 149 |
|    March, 23 2014 00:00:00+0000 | 156 |
| February, 02 2014 00:00:00+0000 |  61 |
| February, 09 2014 00:00:00+0000 |  64 |
| February, 16 2014 00:00:00+0000 |  52 |
| February, 23 2014 00:00:00+0000 |  54 |

如果它符合您的要求，请告诉我。

【讨论】：