无法通过 python 发送电子邮件（gmail）

Question

我有一个代码在半年前就可以使用。它基本上发送电子邮件。

import smtplib
import socket

gmail_user="SENDERMAIL"
gmail_password="SENDERPASS"
to = 'SENDTOTHIS'

email_text = "ADSADSADSA"

try:
    server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
    server.ehlo()
    server.login(gmail_user, gmail_password)
    server.starttls()
    server.sendmail(gmail_user, to, email_text)
    server.close()

    #I was using this code below and it was working. I tried above code but it also did not work.
    #server = smtplib.SMTP("smtp.gmail.com:587")
    #server.ehlo()
    #server.starttls()
    #server.ehlo()
    #server.login(gmail_user, gmail_password)
    #server.sendmail(gmail_user, to, email_text)
    #server.close()
    print("Done")
except Exception as exception:
    print(exception)

这里是例外

(534, b'5.7.14

5.7.14 KL7_2qGSLW9IBjP8dKKgP67bEgyKNc5ls76dnVDZcUlVQjJUQb0JX9BIVi_Agb84vKNOKB

5.7.14 fshB0ngZ_Tn8ocDpDHKavRKXmluVjHo5YM7ADKENtWn4aVTxyvaBlbXRGpA1EBh91bdV-o

5.7.14 pwiAWUHXKmRQEuSNSiFcv68DP4a7ghIu9YKnTyqtUEhGd4HgKtxa4Jz0mhSQDjD13UQWYB

5.7.14 -YEL5Sd2h5YxN8kkSAsK-J_hXMbpy7wNyeCov8lq1Aa3spZzgo> 请通过以下方式登录

5.7.14 您的网络浏览器，然后重试。

5.7.14 了解更多信息，请访问

5.7.14 https://support.google.com/mail/answer/78754 f132-v6sm3660398wme.24 - gsmtp')

我确实尝试过

• 登录 gmail
• 将设备添加到受信任的设备
• 通过 gmail 开启 IMAP
• let less secure apps
• 试过这个：

https://support.google.com/mail/answer/7126229?visit_id=636711453029417344-336837064&rd=2#cantsignin

Answer 1

有很多方法可以解决这个问题。我希望这段代码有所帮助。 您唯一需要做的就是填写所需的变量。

    import socket
    import smtplib
    from email.mime.multipart import MIMEMultipart
    from email.mime.text import MIMEText
    # 
    message = "Your message" # Type your message
    msg = MIMEMultipart()
    password = "********" # Type your password 
    msg['From'] = "from@gmail.com" # Type your own gmail address 
    msg['To'] = "To@gmail.com" # Type your friend's mail address  
    msg['Subject'] = "title" # Type the subject of your message 
    msg.attach(MIMEText(message, 'plain'))
    server = smtplib.SMTP('smtp.gmail.com: 587')
    server.starttls()
    server.login(msg['From'], password)
    server.sendmail(msg['From'], msg['To'], msg.as_string())
    server.quit()

Answer 2

我还可以建议使用更简单的库（smtplib 之上的包装器，以确保不涉及其他因素）....例如yagmail（免责声明：我是开发人员）。

试试看是否可行：

import yagmail
yag = yagmail.SMTP("username", "password")
yag.send(subject="hi")