获取 Android 设备的所有者名称

Question

以下代码可在模拟器上运行，但无法在三星 Galaxy S III 上运行。

    final String[] projection = new String[]
    { ContactsContract.Profile.DISPLAY_NAME };
    String name = null;
    final Uri dataUri = Uri.withAppendedPath(ContactsContract.Profile.CONTENT_URI, ContactsContract.Contacts.Data.CONTENT_DIRECTORY);
    final ContentResolver contentResolver = getContentResolver();
    final Cursor c = contentResolver.query(dataUri, projection, null, null, null);

    try
    {
        if (c.moveToFirst())
        {
            name = c.getString(c.getColumnIndex(ContactsContract.Profile.DISPLAY_NAME));
        }
    }
    finally
    {
        c.close();
    }
    System.out.println(name);

这是一个例外：

12-03 20:57:15.751: E/AndroidRuntime(28172): FATAL EXCEPTION: main
12-03 20:57:15.751: E/AndroidRuntime(28172): java.lang.RuntimeException: Unable to start activity ComponentInfo{ht.smca.flashligh/ht.smca.flashligh.MainActivity}: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2100)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2125)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.access$600(ActivityThread.java:140)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1227)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Handler.dispatchMessage(Handler.java:99)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Looper.loop(Looper.java:137)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.main(ActivityThread.java:4898)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invokeNative(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invoke(Method.java:511)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1006)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:773)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at dalvik.system.NativeStart.main(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172): Caused by: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.LoggingPrintStream.println(LoggingPrintStream.java:298)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at ht.smca.flashligh.MainActivity.onCreate(MainActivity.java:68)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Activity.performCreate(Activity.java:5206)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1083)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2064)
12-03 20:57:15.751: E/AndroidRuntime(28172):    ... 11 more

有什么建议吗？我这样做是为了学习目的，即为了一个研讨会。

Answer 1

这将帮助您获取设备上存储的所有者名称：

Cursor c = getApplication().getContentResolver().query(ContactsContract.Profile.CONTENT_URI, null, null, null, null); 
c.moveToFirst();
textView.setText(c.getString(c.getColumnIndex("display_name")));
c.close();

确保在清单中添加此权限：

<uses-permission android:name="android.permission.READ_CONTACTS"/>

Answer 2

您有 java 空指针异常，因此名称为空。将您的 system.out.println() 放入尝试中，您将不会出现此错误。在得到我不知道的名字之后——Clad

不是我的帖子，而是您的回答： Get Android Device Name（安卓设备型号我不好）

 android.os.Build.MODEL;

这里有两种方法：

How can I get the google username on Android?

How can I get the first name (or full name) of the user of the phone?

Answer 3

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

Answer 4

此代码将为所有者提供完整信息

试试这个代码：

public class EmailFetcher{

    static String getName(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", name = "";
        while (CR.moveToNext())
        {
            name = CR.getString(CR.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        }
        return name;
    }


    static String getEmailId(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", email = "";
        while (CR.moveToNext()) {
            id = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
            email = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
        }
        return email;
    }


    static Cursor getOwner(Context context) {
        String accountName = null;
        Cursor emailCur = null;
        AccountManager accountManager = AccountManager.get(context);
        Account[] accounts = accountManager.getAccountsByType("com.google");
        if (accounts[0].name != null) {
            accountName = accounts[0].name;
            String where = ContactsContract.CommonDataKinds.Email.DATA + " = ?";
            ArrayList<String> what = new ArrayList<String>();
            what.add(accountName);
            Log.v("Got account", "Account " + accountName);
            for (int i = 1; i < accounts.length; i++) {
                where += " or " + ContactsContract.CommonDataKinds.Email.DATA + " = ?";
                what.add(accounts[i].name);
                Log.v("Got account", "Account " + accounts[i].name);
            }
            String[] whatarr = (String[])what.toArray(new String[what.size()]);
            ContentResolver cr = context.getContentResolver();
            emailCur = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, where, whatarr, null);
            if (id != null) {
                // get the phone number
                Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null);
                while (pCur.moveToNext())
                {
                    phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                    Log.v("Got contacts", "phone" + phone);
                }
                pCur.close();
            }
        }
        return emailCur;
    }
}

Answer 5

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

使用上述代码从 android 设备获取所有者名称。这基本上为我的用户获取存储在联系人中的名称。

注意：少数用户会出现如下异常

android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0 at android.database.AbstractCursor.checkPosition(AbstractCursor.java:460) at android.database.AbstractWindowedCursor.checkPosition(AbstractWindowedCursor.java:136) at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:50) at android.database.CursorWrapper.getString(CursorWrapper.java:137)

此异常并非特定于手机或特定于用户。有些用户没有在联系人列表中设置自己的联系人。因此，为了解决这个问题，启动应用程序的用户需要在联系人应用程序中设置第一行，即 ME 联系人。只需在个人信息中输入您的姓名即可生成卡片。

@Leejjon ^^