如何替换 Sendgrid 模板变量？ （在节点 js 中）

Question

这似乎是我缺少的一个简单参数，但我无法弄清楚它到底是什么。

这是我使用“@sendgrid/mail”发送的请求：

email.js:

const sgMail = require('@sendgrid/mail');

function emailRequest() {
    msg = {
      to: 'test+10@gmail.com
      from: 'info@owner.io',
      subject: 'Receipt for Business Expenses',
      template_id: 'db6d11ae-41e4-4e1a-a71b-f5368eb21c9c',
      personalizations: [
        {
          to: 'test+10@gmail.com,
          from: 'info@ownr.io,
          subject: 'Receipt for Business Expenses,
          template_id: 'db6d11ae-41e4-4e1a-a71b-f5368eb21c9c',
          substitutions: {
            ':firstname': 'Bobba',
            ':ordernumber': 'WHAAA',
            ':orderdate': 'today',
            ':ordertime': 'NOW!',
          },
          custom_args: {
            ':firstname': 'Bobba',
            ':ordernumber': 'WHAAA',
            ':orderdate': 'today',
            ':ordertime': 'NOW!',
          },
        },
      ],
      sub: {
        ':firstname': 'Bobba',
        ':ordernumber': 'WHAAA',
        ':orderdate': 'today',
        ':ordertime': 'NOW!',
      },
      substitutions: {
        ':firstname': 'Bobba',
        ':ordernumber': 'WHAAA',
        ':orderdate': 'today',
        ':ordertime': 'NOW!',
      },
    };

  sgMail.setApiKey(process.env.SENDGRID_API_KEY);

  return sgMail
    .send(msg)
    .then(response => {
      return response;
    })
    .catch(err => {
      throw err;
    });
}

电子邮件已发送，但我仍然收到未替换的模板：

sendgrid-nodejs mail.js 的源代码似乎说只要有“替换”，它就会用这些替换初始化邮件类，但它不起作用：

https://github.com/sendgrid/sendgrid-nodejs/blob/master/packages/helpers/classes/mail.js

https://sendgrid.com/docs/API_Reference/Web_API_v3/Mail/index.html

如何正确地将变量替换为模板？我是不是用错包了？

Answer 1

无需指定替换包装器，因为它会假定您默认使用 Handlebars 模板。

const sgMail = require('@sendgrid/mail');
sgMail.setApiKey(process.env.SENDGRID_API_KEY);
const msg = {
  to: 'recipient@example.org',
  from: 'sender@example.org',
  templateId: 'd-f43daeeaef504760851f727007e0b5d0',
  dynamicTemplateData: {
    subject: 'Testing Templates',
    name: 'Some One',
    city: 'Denver',
  },
};
sgMail.send(msg);

Check documentation to learn more

Answer 2

经过一番挖掘，我在他们 github 的问题部分找到了答案。我错过了'substitutionWrappers'。为了让它工作，我所要做的就是在消息中添加“substitutionWrappers”以及“substitutions”：

const msg = {
    to: 'test@email.com'
    from: 'info@gmail.io',
    subject: 'Receipt for Business Expenses',
    template_id: 'da6db3ae-41e4-4e1a-a71b-f5368ab41c9c',
    substitutionWrappers: [':', ''],
    substitutions: {
      firstname: 'Bobba',
      ordernumber: 'WHAAA',
      orderdate: 'today',
      ordertime: 'NOW!',
    },
  };