在 DisplayName 属性上从 Gmail 发送电子邮件错误

Question

当我删除 MailAddress() 的 DisplayName 属性时，下面是我的代码，它工作正常，但接收端邮件在显示名称上显示 EmailID，例如 emailID@gmail.com。

MailMessage mail = new MailMessage();
    mail.From = new System.Net.Mail.MailAddress("emailID@domainName.com");
    // The important part -- configuring the SMTP client
    SmtpClient smtp = new SmtpClient();
    smtp.Port = 587;   // [1] You can try with 465 also, I always used 587 and got success
    smtp.EnableSsl = true;
    smtp.DeliveryMethod = SmtpDeliveryMethod.Network; // [2] Added this
    smtp.UseDefaultCredentials = false; // [3] Changed this
    smtp.Credentials = new NetworkCredential(mail.From.ToString(), "password");  // [4] Added this. Note, first parameter is NOT string.
    smtp.Host = "smtp.gmail.com";
    mail.IsBodyHtml = true;
    mail.Subject = Subject;
    mail.Body = Body;
    mail.To.Add(new MailAddress(To));
    smtp.Send(mail);
    mail.Dispose();

当我添加 MailAddress() 的显示名称时，我收到此错误消息。

System.Net.Mail.SmtpException：SMTP 服务器需要安全 连接或客户端未通过身份验证。服务器响应 是：5.5.1 需要身份验证。了解更多信息 System.Net.Mail.MailCommand.CheckResponse（SmtpStatusCode statusCode， 字符串响应）在 System.Net.Mail.SmtpTransport.SendMail(MailAddress 发件人，MailAddressCollection 收件人，字符串传递通知， Boolean allowUnicode、SmtpFailedRecipientException& 异常）在 System.Net.Mail.SmtpClient.Send(MailMessage message) at ***

我哪里错了？

Answer 1

var client = new SmtpClient
    {
     Host = "smtp.googlemail.com",
     Port = 587,
     UseDefaultCredentials = false,
     DeliveryMethod = SmtpDeliveryMethod.Network,
     EnableSsl = true,
     Credentials = new NetworkCredential(SmtpUserName, SmtpUserPassword);
    };

client.Send(mail);

其中mail 是MailMessage 的一个实例

private static SecureString _smtpPassword;

    public static SecureString SmtpUserPassword
    {
        get
        {
            if (_smtpPassword != null)
                return _smtpPassword;

            _smtpPassword = new SecureString();

            foreach (var c in "your password here")
                _smtpPassword.AppendChar(c);

            _smtpPassword.MakeReadOnly();

            return _smtpPassword;
        }
    }