【发布时间】:2021-03-20 04:19:48
【问题描述】:
我正在尝试根据两个复选框的状态更改字符串的样式。一个是boldCheck,另一个是italicCheck。但是,当我运行程序时,它会在paintComponent 中绘制默认字符串,并且两个复选框不起作用?并且代码本身存在实际问题,但问题似乎是我制作此代码的方式。任何有关解决此问题的帮助将不胜感激。
import java.awt.*;
import java.awt.event.ItemEvent;
import java.awt.event.ItemListener;
public class JavaTest {
public static void main(String[] args) {
JFrame window = new JFrame("HomeWork");
DrawMessage message = new DrawMessage();
window.add(message);
window.setVisible(true);
window.setSize(600,300);
window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
static class DrawMessage extends JPanel{
private static final JCheckBox boldCheck = new JCheckBox("Bold");
private static final JCheckBox italicCheck = new JCheckBox("Italic");
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
g.setFont(new Font("TimesRoman", Font.PLAIN, 20));
g.setColor(Color.blue);
g.drawString("Welcome to java Programing", 40, 40);
setBackground(Color.yellow);
add(boldCheck);
add(italicCheck);
CheckBoxHandler handler = new CheckBoxHandler();
boldCheck.addItemListener(handler);
italicCheck.addItemListener(handler);
}
static private class CheckBoxHandler extends DrawMessage implements ItemListener{
private int valBold = Font.PLAIN;
private int valItalic = Font.PLAIN;
@Override
public void itemStateChanged(ItemEvent e) {
if(e.getSource() == boldCheck){
valBold = boldCheck.isSelected() ? Font.BOLD: Font.PLAIN;
}
if(e.getSource() == italicCheck){
valItalic = italicCheck.isSelected() ? Font.ITALIC : Font.PLAIN;
}
DrawMessage obj = new DrawMessage();
obj.setFont(new Font("TimesRoman", valBold + valItalic, 20));
}
}
}
}
【问题讨论】: