仅在子级别上应用 jq 过滤器，保持 JSON 的其余部分完好无损答案

【问题标题】：apply jq filter on sub level only, keeping the rest of the JSON intact仅在子级别上应用 jq 过滤器，保持 JSON 的其余部分完好无损
【发布时间】：2020-03-13 19:38:47
【问题描述】：

给定一个嵌套对象，是否可以只对 json 的子级别应用过滤器，然后将包含应用过滤器的子级别的原始 json 作为输出？

例如，如果我有这样的 json：

{"k1": "v1",
 "k2": "v2",
 "k3": "v3",
 "k4": [],
 "records": [{
        "kk1": "vv1",
        "kk2": ["vv2"],
        "releases": [{"kkk1":"vvv1"}, 
                     {"parties":[{"name":"value",
                                  "kkkk1":"value"}, 
                                 {"name":"value",
                                  "kkkk1":"value"}]}],
        "kk4": "vv4",

        "kk5": "vv5"},
        {
        "kk1": "o_vv1",
        "kk2": ["o_vv2"],
        "releases": [{"kkk1":"o_vvv1"}, 
                     {"parties":[{"name":"o_value",
                                  "kkkk1":"o_value"}, 
                                {"name":"o_value",
                                 "kkkk1":"o_value"}]}],
        "kk4": "o_vv4",

        "kk5": "o_vv5"}],
 "k6":"v6"}

我希望输出同样的 json，但将 .[].records[].releases[].parties 中的嵌套对象展平，因此所需的输出应该是：

previous keys
...
 "records": [{
        "kk1": "vv1",
        "kk2": ["vv2"],
        "releases": [{"kkk1":"vvv1"}, 
                     {"parties.0.name":"value",
                      "parties.0.kkkk1":"value", 
                      "parties.1.name":"value",
                      "parties.1.kkkk1": "value"}]
       "kk4": "vv4",
       "kk5": "vv5"}, 
       {
       "kk1": "other_vv1",
       "kk2": ["other_vv2"],
       "releases": [{"kkk1":"vvv1"}, 
                    {"parties.0.name":"value",
                     "parties.0.kkkk1":"value", 
                     "parties.1.name":"value",
                     "parties.1.kkkk1": "value"}]
       "kk4": "other_vv4",
       "kk5": "other_vv5"},
...
following keys

编辑：当前 jq 命令：

 jq '.[].records[].releases[].parties| . as $ho | reduce paths(scalars) as $path ({}; . + {($path | map(tostring) | join(".")): $ho | getpath($path)})'

【问题讨论】：

您的示例输入与您发布的实际数据不匹配；您的示例的有效解决方案可能不适用于您的实际输入，反之亦然。请修复它并告诉我们，另见minimal reproducible example

标签： json jq flatten

【解决方案1】：

如果你只想替换一个子部分，你可以使用 |= 而不是 | ，就在 .parties 之后

所以我认为这将实现您的目标：

.[].records[].releases[].parties |= 
  (. as $ho 
   | reduce paths(scalars) as $path ({};
       . + {($path | map(tostring) | join(".")):
             $ho | getpath($path)}))

【讨论】：