您好，我这里有一个问题，我有 2 个表，其中一个名为 ecom_registered_users 和 points。
points 表有名为 points.customer_id 的列，与 ecom_registered_users.id 相同。
在我的 cms 上，我最近有一个查看所有用户信息的页面，我添加了导出按钮以将 excel 表导出为报告，以防客户到目前为止需要它， 问题是我想得到每个客户的总分，我的意思是计算它们的总和，然后当我导出数据时，我应该找到用户名、他的电话号码、他的电子邮件和 + 我的 excel 表中的另一列，其中包含每个用户的总分，我该怎么做
这是我的积分表结构 points table
这是我的 ecom_registered_users
这是我应该运行查询的导出代码块
【问题讨论】：
好的，所以我通过使用如下视图来解决我的问题：
1-查看total_points_plus（所有加号为'+'的点）
create view total_points_plus as select customer_id , sum(number) as plus from points where (customer_id in (select id from ecom_registered_users) and plus_minus = '+') group by customer_id
2-查看total_points_plus（所有加号为'-'的点）
create view total_points_minus as select customer_id , sum(number) as minus from points where (customer_id in (select id from ecom_registered_users) and plus_minus = '-') group by customer_id
3-视图对以上视图进行简单计算（总计）
create VIEW total_points AS select total_points_plus.customer_id , plus , IFNULL( minus , 0) as minus , (plus - IFNULL(minus , 0)) as grand_total from total_points_plus left join total_points_minus on total_points_plus.customer_id = total_points_minus.customer_id
4- 将最终报告也作为视图获取
create view final_report as select ecom_registered_users.userName as name , ecom_registered_users.userEmail as email , ecom_registered_users.userMobile as mobile , total_points.grand_total as total from ecom_registered_users left join total_points on ecom_registered_users.id = total_points.customer_id
就是这样，然后在我的 php 导出代码中，我简单而优雅地执行此查询：
<?php $query = "SELECT * FROM final_report " ; ?>
【讨论】：
试试这个
<?php
session_start();
$sql= mysql_query("$qry = "SELECT eru.userName, eru.userMobile, eru.userEmail, SUM(p.number)
FROM ecom_registered_users eru
JOIN points p ON eru.customer_id = p.id
WHERE eru.customer_id = /*insert customer id here*/;"") or die(print "Gagal Download :".mysql_error());
$columns_total = mysql_num_fields($sql);
// Get The Field Name
for ($i = 0; $i < $columns_total; $i++) {
$heading = mysql_field_name($sql, $i);
$output .= '"'.$heading.'",';
}
$output .="\n";
// Get Records from the table
while ($row = mysql_fetch_array($sql)) {
for ($i = 0; $i < $columns_total; $i++) {
$output .='"'.$row["$i"].'",';
}
$output .="\n";
}
// Download the file
$filename = "filename.csv"; //Ur File name
header('Content-type: application/csv');
header('Content-Disposition: attachment; filename='.$filename);
echo $output;
exit;
?>
【讨论】：
WHERE eru.customer_id = /*insert customer id here*/
很遗憾，我看不到您的代码块，所以我不确定您已经尝试过什么，但您似乎只需要这样的声明：
$qry = "SELECT eru.userName, eru.userMobile, eru.userEmail, SUM(p.number)
FROM ecom_registered_users eru
JOIN points p ON eru.customer_id = p.id
WHERE eru.customer_id = /*insert customer id here*/;";
此查询应该为您提供一位用户想要的结果。如果您需要一页上的所有用户，您只需将 GROUP BY 和 ORDER 添加到查询中。如果您向我展示您的代码，我可以编辑此答案以帮助您更多。
【讨论】：
SELECT eru.userName, eru.userMobile, eru.userEmail, SUM(p.number) FROM ecom_registered_users eru JOIN points p ON eru.customer_id = p.id GROUP BY eru.customer_id ORDER BY SUM(p.number)