【发布时间】:2021-07-06 08:00:58
【问题描述】:
$data = Product::with('items')->whereBetween('date', ['2000-01-01', '2000-01-31'])->get();
dump($data);
输出
[
0=>[
"id"=>11
"type"=>"food"
"items"=>[
0 =>[
"id"=>333
"set_id"=>1
"member_price"=> 22
"non_member_price"=> 0
]
1 =>[
"id"=>444
"set_id"=>2
"member_price"=> 0
"non_member_price"=> 33
]
]
]
1=>[
"id"=>22
"type"=>"food"
"items"=>[
0 =>[
"id"=>444
"set_id"=>1
"member_price"=> 44
"non_member_price"=> 0
]
1 =>[
"id"=>555
"set_id"=>2
"member_price"=> 0
"non_member_price"=> 55
]
]
]
2=>[
"id"=>33
"type"=>"beverage"
"items"=>[
0 =>[
"id"=>666
"set_id"=>1
"member_price"=> 66
"non_member_price"=> 0
]
1 =>[
"id"=>777
"set_id"=>2
"member_price"=> 0
"non_member_price"=> 77
]
]
]
]
我的问题:当 type 相同且 set_id 相同时,如何使用 Laravel 雄辩查询对 items 的关系表中的字段 member_price 和 non_member_price 求和?
我希望得到如下结果响应
[
0=>[
"id"=>11
"type"=>"food"
"items"=>[
0 =>[
"id"=>333
"set_id"=>1
"member_price"=> 66
"non_member_price"=> 0
]
1 =>[
"id"=>444
"set_id"=>2
"member_price"=> 0
"non_member_price"=> 88
]
]
]
1=>[
"id"=>33
"type"=>"beverage"
"items"=>[
0 =>[
"id"=>666
"set_id"=>1
"member_price"=> 66
"non_member_price"=> 0
]
1 =>[
"id"=>777
"set_id"=>2
"member_price"=> 0
"non_member_price"=> 77
]
]
]
]
【问题讨论】:
标签: php laravel eloquent eloquent-relationship