寻求正确的MySql“IF”方法指南

Question

我需要获取特定列值的数据，但还包括项目IF 他们启用了inventory 并且stock 大于0。

以下只是一个概念查询，可以直观地了解我的意图。当然不行。

SELECT id, name, image, price
FROM shop
WHERE published = 1
AND price > 2
  /*concept clause here*/
    IF(inventory = 1 AND stock > 0, include, ignore)
  /*end concept*/
ORDER BY RAND() 
LIMIT 30

表结构

shop
__________________________________________
|id|name  |image   |price|inventory|stock|
------------------------------------------
|4 |widget|pic.jpg |6    |1        |12   |
------------------------------------------
|5 |bolt  |bolt.jpg|7    |0        |0    |
------------------------------------------
|6 |trowel|trow.jpg|12   |1        |0    |
__________________________________________

想要的结果

数组

[
    ['id'=>4,'name'=>'widget','image'=>'pic.jpg','price'=>6],
    ['id'=>5,'name'=>'bolt','image'=>'bolt.jpg','price'=>7]
]

启用inventory 但stock 值为0 的行将不在数组中。

如何根据这种情况取得成果？

---

有效但“肮脏”的解决方案

我已经运行了两次类似的查询，然后合并数组

获取未启用库存的商品

SELECT id, name, image, price
FROM shop
WHERE published = 1
AND price > 2
AND inventory = 0 
ORDER BY RAND() 
LIMIT 30

获取已启用库存且有库存的商品

SELECT id, name, image, price
FROM shop
WHERE published = 1
AND price > 2
AND inventory = 1 
AND stock > 0 
ORDER BY RAND() 
LIMIT 30

合并数组

$merged = array_merge($withoutInventory, $withInventory);

Answer 1

样本数据和预期结果将有助于澄清。我认为您需要将列选择和 OR 括起来

SELECT id, name, image, price
FROM shop
WHERE (published = 1 AND price > 2) OR
      (inventory = 1 AND stock > 0)
ORDER BY RAND() 
LIMIT 30