根据编号显示错误信息。的尝试？答案

【问题标题】：Display a error message according to the no. of tries?根据编号显示错误信息。的尝试？
【发布时间】：2014-05-05 22:26:17
【问题描述】：

我是 Java 和 Android 的新手。在下面的 sn-p 中，当用户名和密码不正确时，我会显示一条错误消息。现在我需要在 2 次错误尝试后在错误消息中添加一些额外信息。如果我需要设置一个计数器来识别尝试？我该怎么做？

public void testBadCredentials() throws Exception {
    RestClientFactoryTest.setPrefixAllInstances("login-failure");
    XMLRPCFactoryTest.setPrefixAllInstances("login-failure");
    mSolo.enterText(0, "test"); //username 
    mSolo.enterText(1, "test"); //password
    mSolo.clickOnText(mSolo.getString(R.string.sign_in));
    boolean errorMessageFound = mSolo.searchText(mSolo.getString(R.string.username_or_password_incorrect));
    assertTrue("Error message not found", errorMessageFound);
}

【问题讨论】：

标签： java android if-statement conditional-statements

【解决方案1】：

 private static n0_attamp = 0;
public void testBadCredentials() throws Exception {
n0_attamp++;
RestClientFactoryTest.setPrefixAllInstances("login-failure");
XMLRPCFactoryTest.setPrefixAllInstances("login-failure");
mSolo.enterText(0, "test"); //username 
mSolo.enterText(1, "test"); //password
mSolo.clickOnText(mSolo.getString(R.string.sign_in));
boolean errorMessageFound = mSolo.searchText(mSolo.getString(R.string.username_or_password_incorrect));
if(n0_attamp = 3)
{ 
  assertTrue("3rd try", errorMessageFound);
  //reinitialize counter
   n0_attamp = 0; 
 }
 else
assertTrue("Error message not found", errorMessageFound);
}

【讨论】：