根据其他列值删除数据框的值

Question

我想根据另一列中的值从数据框的特定列中删除单元格值。

对于“匹配”列中包含“TRUE”的每一行，应删除“品牌总差异”列中的值（不是零，只是空）。

variable	Difference Magnitude	Total Difference by Brand	Total Difference by Location	match
Total New Funding Sources	1406904	5031189	4373182	FALSE
Total New Funding Sources	75821	5031189	4373182	TRUE
Total New Funding Sources	33692	5031189	4373182	TRUE
Total New Funding Sources	2627094	5031189	4373182	TRUE
Total New Funding Sources	400000	500000	4373182	FALSE
Total New Funding Sources	500000	500000	4373182	TRUE
Total New Funding Sources	1406904	5131189	4373182	FALSE
Total New Funding Sources	75821	5131189	4373182	TRUE
Total New Funding Sources	33692	5131189	4373182	TRUE

数据框应如下所示：

variable	Difference Magnitude	Total Difference by Brand	Total Difference by Location	match
Total New Funding Sources	1406904	5031189	4373182	FALSE
Total New Funding Sources	75821		4373182	TRUE
Total New Funding Sources	33692		4373182	TRUE
Total New Funding Sources	2627094		4373182	TRUE
Total New Funding Sources	400000	500000	4373182	FALSE
Total New Funding Sources	500000		4373182	TRUE
Total New Funding Sources	1406904	5131189	4373182	FALSE
Total New Funding Sources	75821		4373182	TRUE
Total New Funding Sources	33692		4373182	TRUE

谢谢

Answer 1

你可以试试这个：

import pandas as pd

df = pd.DataFrame(
    {
        "variable": {
            0: "Total New Funding Sources",
            1: "Total New Funding Sources",
            2: "Total New Funding Sources",
            3: "Total New Funding Sources",
        },
        "Difference Magnitude": {0: 1406904.0, 1: 75821.0, 2: 33692.0, 3: 2627094.0},
        "Total Difference by Brand": {
            0: 5031189.0,
            1: 5031189.0,
            2: 5031189.0,
            3: 5031189.0,
        },
        "Total Difference by Location": {
            0: 4373182.0,
            1: 4373182.0,
            2: 4373182.0,
            3: 4373182.0,
        },
        "match": {0: False, 1: True, 2: True, 3: True},
    }
)

df.loc[df["match"].eq(True), "Total Difference by Brand"] = ""

print(df[["variable", "Total Difference by Brand"]])
# Outputs
                    variable Total Difference by Brand
0  Total New Funding Sources                 5031189.0
1  Total New Funding Sources
2  Total New Funding Sources
3  Total New Funding Sources