【问题标题】:How do I output pdo results in JSON format for use in javascript function?如何以 JSON 格式输出 pdo 结果以用于 javascript 函数?
【发布时间】:2019-05-07 07:28:07
【问题描述】:

当我在 PHP 中回显结果时,它们似乎被正确格式化为 JSON,但是当我回显将它们保存在 JavaScript 中的变量时,我得到一个“未捕获的语法错误:意外的标识符”错误(当我删除 echo 语句)。代码如下:

$charset="utf8";
$dsn = "mysql:host=$host;dbname=$db;charset=$charset";
$options = [
    PDO::ATTR_ERRMODE            => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC,
    PDO::ATTR_EMULATE_PREPARES   => false,
];
try {
    $pdo = new PDO($dsn, $user, $pass, $options);
} catch (\PDOException $e) {
    throw new \PDOException($e->getMessage(), (int)$e->getCode());
}

$page = 'nike';
$stmt = $pdo->prepare('SELECT `url`, `alt`, `model`, `desc` FROM images WHERE page_id = (select id from pages where title = ?)');
$stmt->execute([$page]);
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo 'results are:' . $results; //array
$json = json_encode($results);
echo 'json is: ' . $json;// seemingly correct json formatted result set  

如果我像这样直接在 JavaScript 中回显 $json 变量:

var imgs="<?php echo $json; ?>";

我收到“Uncaught SyntaxError: Unexpected identifier”错误消息,当我删除该行时该错误消息消失。 我的 javascript 函数期望 var imgs 是:

var imgs = [
    {"url": "images/adidas_large/1.png", "model": "Kumacross", "desc": ""},
    {"url": "images/adidas_large/2.png", "model": "fig 2 model", "desc": "fig 2 desc"},
    {"url": "images/adidas_large/3.png", "model": "fig 3 model", "desc": "fig 3 desc"},
    {"url": "images/adidas_large/4.png", "model": "fig 4 model", "desc": "fig 4 desc"},
    {"url": "images/adidas_large/5.png", "model": "fig 5 model", "desc": "fig 5 desc"},
    {"url": "images/adidas_large/6.png", "model": "fig 6 model", "desc": "fig 6 desc"},
    {"url": "images/adidas_large/7.png", "model": "fig 7 model", "desc": "fig 7 desc"},
    {"url": "images/adidas_large/8.png", "model": "fig 8 model", "desc": "fig 8 desc"},
    {"url": "images/adidas_large/9.png", "model": "fig 9 model", "desc": "fig 9 desc"}
];

... 并在提供此硬编码时工作。所以我的问题是,如何正确输出 JSON 格式的 PDO 查询结果以用于 JavaScript 函数?

【问题讨论】:

    标签: javascript json pdo


    【解决方案1】:

    我通过 json_encoding $results 在 javascript 而不是 php 中解决了这个问题

    var imgs = "<?php echo json_encode($results); ?>";
    

    到

    var imgs=<?php echo json_encode($results); ?>;
    

    【讨论】:

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