【问题标题】:Extracting a zipfile to memory?将压缩文件提取到内存?
【发布时间】:2012-06-10 03:41:21
【问题描述】:
如何将 zip 提取到内存中?
我的尝试(在 .getvalue() 上返回 None):
from zipfile import ZipFile
from StringIO import StringIO
def extract_zip(input_zip):
return StringIO(ZipFile(input_zip).extractall())
【问题讨论】:
标签:
python
memory
zip
zipfile
stringio
【解决方案1】:
extractall 提取到文件系统,所以你不会得到你想要的。要在内存中提取文件,请使用ZipFile.read() 方法。
如果你真的需要内存中的全部内容,你可以这样做:
def extract_zip(input_zip):
input_zip=ZipFile(input_zip)
return {name: input_zip.read(name) for name in input_zip.namelist()}
【解决方案2】:
可能的原因:
1.此模块目前不处理多磁盘 ZIP 文件。
(或)
2.检查 StringIO.getvalue() 天气 Unicode 错误即将到来。
【解决方案3】:
如果您经常使用内存存档,我建议您制作一个工具。像这样的:
# Works in Python 2 and 3.
try:
import BytesIO
except ImportError:
from io import BytesIO # Python 3
import zipfile
class InMemoryZip(object):
def __init__(self):
# Create the in-memory file-like object for working w/IMZ
self.in_memory_zip = BytesIO()
# Just zip it, zip it
def append(self, filename_in_zip, file_contents):
# Appends a file with name filename_in_zip and contents of
# file_contents to the in-memory zip.
# Get a handle to the in-memory zip in append mode
zf = zipfile.ZipFile(self.in_memory_zip, "a", zipfile.ZIP_DEFLATED, False)
# Write the file to the in-memory zip
zf.writestr(filename_in_zip, file_contents)
# Mark the files as having been created on Windows so that
# Unix permissions are not inferred as 0000
for zfile in zf.filelist:
zfile.create_system = 0
return self
def read(self):
# Returns a string with the contents of the in-memory zip.
self.in_memory_zip.seek(0)
return self.in_memory_zip.read()
# Zip it, zip it, zip it
def writetofile(self, filename):
# Writes the in-memory zip to a physical file.
with open(filename, "wb") as file:
file.write(self.read())
if __name__ == "__main__":
# Run a test
imz = InMemoryZip()
imz.append("testfile.txt", "Make a test").append("testfile2.txt", "And another one")
imz.writetofile("testfile.zip")
print("testfile.zip created")