Laravel 雄辩的查询

Question

我有 3 个表，分别名为 cash_manages、outlets 和 delivery_boys，结构是

        //outlets
        id name
        1  utha
        2  alabama

        //delivery_boys
        id outlet_id  name
        1     1       John 
        2     1       Mike
        3     2       Alex

        //cash_manage
        id   source_type   source_id   destination_id   status     amount
        1      admin          1             2            give       500 
        2      admin          2             1            give       350   
        3      deliveryBoy    1             2            receive    300 
        4      admin          2             2            give       500
        5      admin          2             1            give       800 
        6      user           1             1            give       600
        7      user           2             2            give       450

   //the logic
    1-> if source_type is admin then the source_id is outlet_id and the cash is **GIVEN** to destination_type delivery_boy_id

    2-> if source_type is deliveryBoy then the source_id is delivery_boy_id and the cash is **Received** by destination_type outlet_id(admin)

我想在视图中得到如下结果（带送货员的现金）

num   outlet   delivery_boy   cash_taken  cash_returned  cash_has 
1     alabama     John          1150          300          1050
2     alabama     mike          500           0            500

我加入了所有三个表，并且能够获得 Outlet Name 和 Delivery Boy Name。 现在我被困在计算部分

public function index(Request $request) 
{
    $outlet_id = $request->outlet_id;

    $transaction_list = DeliveryCashManage::leftJoin('outlets','outlets.id','delivery_cash_manages.source_id')
                                          ->leftJoin('delivery_boys','delivery_boys.id','destination_id')
                                          ->where('source_type', 'admin')
                                          ->where('source_id', $outlet_id)
                                          ->select('delivery_cash_manages.id','outlets.name as outlet','delivery_boys.name as delivery_boy','amount')
                                          ->groupBy('delivery_boys.name')
                                          ->get();

    return view('pages.manager.cash');
}

我收到以下错误

SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'ideal_chicken.delivery_cash_manages.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by (SQL: select `delivery_cash_manages`.`id`, `outlets`.`name` as `outlet`, `delivery_boys`.`name` as `delivery_boy`, `amount` from `delivery_cash_manages` left join `outlets` on `outlets`.`id` = `delivery_cash_manages`.`source_id` left join `delivery_boys` on `delivery_boys`.`id` = `destination_id` where `source_type` = admin and `source_id` = 1 group by `destination_id`)

我认为我的查询或逻辑有误，请帮助解决此问题

谢谢

Answer 1

这不是完整的答案，但很接近。不过，无论我如何处理数据，我都不知道您是如何提出cash_has 的。此外，我将其保留为原始 SQL，因为我觉得它会更有帮助，并且转换回查询生成器应该不难。我也不知道确切的列名，因此您可能需要修复其中的一些。

SELECT
    COALESCE(outlets_admin.name, outlets.name) AS outlet, 
    COALESCE(boys_admin.name, boys.name) AS delivery_boy,
    SUM(IF(cm.source_type = 'admin', amount, 0)) AS cash_taken,
    SUM(IF(cm.source_type = 'deliveryBoy', amount, 0)) AS cash_returned,
    SUM(IF(cm.source_type = 'admin', amount, 0)) - SUM(IF(cm.source_type = 'deliveryBoy', amount, 0)) AS cash_has
FROM delivery_cash_manages cm
LEFT JOIN outlets ON outlets.id = cm.destination_id AND cm.source_type = 'deliveryBoy'
LEFT JOIN delivery_boys boys ON boys.id = cm.source_id AND cm.source_type = 'deliveryBoy'
LEFT JOIN outlets outlets_admin ON outlets_admin.id = cm.source_id AND cm.source_type = 'admin'
LEFT JOIN delivery_boys boys_admin ON boys_admin.id = cm.destination_id AND cm.source_type = 'admin'
WHERE COALESCE(outlets.id, outlets_admin.id) = '2'  #  This is where you plug in your $outlet_id
GROUP BY outlet, delivery_boy

您在查询中遇到错误的原因是，如果您按任何内容进行分组，则需要按您选择的所有非聚合列（sum、max、avg 等函数）进行分组。