Laravel 分页合并

Question

我在我的项目中使用 laravel 4。 我对 4 个表的选择结果进行了分页，我想将它们传递到一个变量中查看。

$vehicles = DB::table('vehicle')->orderBy('postTime','DESC')->paginate(8);
$estates = DB::table('estate')->orderBy('postTime','DESC')->paginate(8);
$tradings = DB::table('trading')->orderBy('postTime','DESC')->paginate(8);
$jobs = DB::table('job')->orderBy('postTime','DESC')->paginate(8);

但我无法使用 array_merge() 合并它们。分页后我也试过->to_array()，还是不行。

有人可以帮我吗？

编辑

正如@Turgut Sarıçam 建议的那样，我使用getItems() 作为我的结果，这是我的代码：

public static function index(){
    $minVehicle = DB::table('vehicle')->min('price');
    $maxVehicle = DB::table('vehicle')->max('price');
    $minEstate = DB::table('estate')->min('price');
    $maxEstate = DB::table('estate')->max('price');
    $minTrading = DB::table('trading')->min('price');
    $maxTrading = DB::table('trading')->max('price');
    if($minVehicle == 'توافقی')
        $minVehicle = 0;
    if($maxVehicle == 'توافقی')
        $maxVehicle = 0;
    if($minEstate == 'توافقی')
        $minEstate = 0;
    if($maxEstate == 'توافقی')
        $maxEstate = 0;
    if($minTrading == 'توافقی')
        $minTrading = 0;
    if($maxTrading == 'توافقی')
        $maxTrading = 0;
    $vehicles = DB::table('vehicle')->orderBy('postTime','DESC')->paginate(8);
    $estates = DB::table('estate')->orderBy('postTime','DESC')->paginate(8);
    $tradings = DB::table('trading')->orderBy('postTime','DESC')->paginate(8);
    $jobs = DB::table('job')->orderBy('postTime','DESC')->paginate(8);
    $allResults = array_merge($vehicles,$jobs);
    //echo "<meta charset='UTF8'><pre>";
    //return die(print_r($allResults));
    return View::make('search')->with(
        array(
            'minVehicle' => $minVehicle,
            'maxVehicle' => $maxVehicle,
            'minEstate' => $minEstate,
            'maxEstate' => $maxEstate,
            'minTrading' => $minTrading,
            'maxTrading' => $maxTrading,
            'ads' => $allResults
        )
    );
}

转储 $allResults（我评论过的地方）有一些结果。 我无法显示确切的结果，但这里是它的示例：

Array
(
[0] => stdClass Object
    (
        [id] => 243
        [tableName] => vehicle
    )

[1] => stdClass Object
    (
        [id] => 239
        [tableName] => vehicle
    )

[2] => stdClass Object
    (
        [id] => 235
        [tableName] => vehicle
    )

[3] => stdClass Object
    (
        [id] => 231
        [tableName] => vehicle
    )

[4] => stdClass Object
    (
        [id] => 227
        [tableName] => vehicle
    )

[5] => stdClass Object
    (
        [id] => 223
        [tableName] => vehicle
    )

[6] => stdClass Object
    (
        [id] => 219
        [tableName] => vehicle
    )

[7] => stdClass Object
    (
        [id] => 215
        [tableName] => vehicle
    )

[8] => stdClass Object
    (
        [id] => 4
        [tableName] => job
    )

[9] => stdClass Object
    (
        [id] => 3
        [tableName] => job
    )

)

虽然结果似乎是公平的，但没有返回任何视图。只是一张白纸

Answer 1

你应该先拿到物品。试试这样：

$allResults = array_merge($vehicles->items(), $estates->items(), $tradings->items(), $jobs->items());

编辑：我猜你可以在 Laravel 4 中使用getItems() 函数获取项目。以上是 Laravel 5，我的错。

Answer 2

您正在处理从查询返回的集合。不要认为数组合并是正确的方法尝试使用集合合并。

laravel 4 也支持集合合并。 试试这个

$merged_collection = $vehicles->merge($estates)->merge($tradings)->merge($jobs);