我想创建一个方法，它可以获取任何文件并将其作为 0 和 1 的数组读取，即它的二进制代码。我想将该二进制代码保存为文本文件。你能帮助我吗？谢谢。
【问题讨论】：
又快又脏的版本：
byte[] fileBytes = File.ReadAllBytes(inputFilename);
StringBuilder sb = new StringBuilder();
foreach(byte b in fileBytes)
{
sb.Append(Convert.ToString(b, 2).PadLeft(8, '0'));
}
File.WriteAllText(outputFilename, sb.ToString());
【讨论】：
好吧，阅读它并不难，只需使用 FileStream 读取一个字节[]。除非您将 1 和 0 转换为十六进制，否则将其转换为文本通常是不可能的或有意义的。使用 BitConverter.ToString(byte[]) 重载很容易做到这一点。您通常希望在每行中转储 16 或 32 个字节。您可以使用 Encoding.ASCII.GetString() 尝试将字节转换为字符。执行此操作的示例程序：
using System;
using System.IO;
using System.Text;
class Program {
static void Main(string[] args) {
// Read the file into <bits>
var fs = new FileStream(@"c:\temp\test.bin", FileMode.Open);
var len = (int)fs.Length;
var bits = new byte[len];
fs.Read(bits, 0, len);
// Dump 16 bytes per line
for (int ix = 0; ix < len; ix += 16) {
var cnt = Math.Min(16, len - ix);
var line = new byte[cnt];
Array.Copy(bits, ix, line, 0, cnt);
// Write address + hex + ascii
Console.Write("{0:X6} ", ix);
Console.Write(BitConverter.ToString(line));
Console.Write(" ");
// Convert non-ascii characters to .
for (int jx = 0; jx < cnt; ++jx)
if (line[jx] < 0x20 || line[jx] > 0x7f) line[jx] = (byte)'.';
Console.WriteLine(Encoding.ASCII.GetString(line));
}
Console.ReadLine();
}
}
【讨论】：
您可以使用BinaryReader 读取每个字节，然后使用BitConverter.ToString(byte[]) 找出每个字节在二进制中的表示方式。
然后您可以使用此表示并将write 写入文件。
【讨论】：
using (FileStream fs = File.OpenRead(binarySourceFile.Path))
using (BinaryReader reader = new BinaryReader(fs))
{
// Read in all pairs.
while (reader.BaseStream.Position != reader.BaseStream.Length)
{
Item item = new Item();
item.UniqueId = reader.ReadString();
item.StringUnique = reader.ReadString();
result.Add(item);
}
}
return result;
【讨论】：
使用简单的FileStream.Read 然后用Convert.ToString(b, 2) 打印出来
【讨论】：
一般来说，我真的看不出有什么可行的方法来做到这一点。我已经用尽了早期 cmets 给你的所有选项，但它们似乎不起作用。你可以试试这个：
`private void button1_Click(object sender, EventArgs e)
{
Stream myStream = null;
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "This PC\\Documents";
openFileDialog1.Filter = "All Files (*.*)|*.*";
openFileDialog1.FilterIndex = 1;
openFileDialog1.RestoreDirectory = true;
openFileDialog1.Title = "Open a file with code";
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
string exeCode = string.Empty;
using (BinaryReader br = new BinaryReader(File.OpenRead(openFileDialog1.FileName))) //Sets a new integer to the BinaryReader
{
br.BaseStream.Seek(0x4D, SeekOrigin.Begin); //The seek is starting from 0x4D
exeCode = Encoding.UTF8.GetString(br.ReadBytes(1000000000)); //Reads as many bytes as it can from the beginning of the .exe file
}
using (BinaryReader br = new BinaryReader(File.OpenRead(openFileDialog1.FileName)))
br.Close(); //Closes the BinaryReader. Without it, opening the file with any other command will result the error "This file is being used by another process".
richTextBox1.Text = exeCode;
}
}`
这是“打开...”按钮的代码，但这里是“保存...”按钮的代码：
` private void button2_Click(object sender, EventArgs e) { SaveFileDialog save = new SaveFileDialog();
save.Filter = "All Files (*.*)|*.*";
save.Title = "Save Your Changes";
save.InitialDirectory = "This PC\\Documents";
save.FilterIndex = 1;
if (save.ShowDialog() == DialogResult.OK)
{
using (BinaryWriter bw = new BinaryWriter(File.OpenWrite(save.FileName))) //Sets a new integer to the BinaryReader
{
bw.BaseStream.Seek(0x4D, SeekOrigin.Begin); //The seek is starting from 0x4D
bw.Write(richTextBox1.Text);
}
}
}`
这是保存按钮。这工作正常，但只显示“！这不能在 DOS 模式下运行！” - 否则，如果你能解决这个问题，我不知道该怎么办。
【讨论】：