【发布时间】:2019-04-18 08:31:23
【问题描述】:
如何使用其 ID 填充每个复选框?愚蠢的事情被卡住了,但任何事情都会有所帮助。目前它正在填充每个复选框。
$total_row = $data->count();
$output = "";
if ($total_row > 0) {
foreach ($data as $row) {
$roleNames = '';
$userRoles = $row->roles;
$checked = '';
foreach (Role::all() as $roles1) {
if (true) {
$checked = 'checked="checked"';
}
$roleNames .= $roles1->role != null ? $roles1->role.' '.'<input type="checkbox" '.$checked.' name="role" value="'.$roles1->id.'" class="checkbox" id="checkboxId">'.' ' : '';
}
$output .= '
<tr>
<td>'.$row->surname.'</td>
<td>'.$row->name.'</td>
<td>'.$row->phone.'</td>
<td>'.$roleNames.'</td>
<td>'.$userRoles.'</td>
<td><button type="button" id="rowId" class="remove-button btn btn-danger" data-id="'.$row->id.'">
<div class="close">x</div>
</button></td>
</tr>
';
}
编辑: $userRoles 正在打印所有用户及其角色的 JSON
[{"id":1,"role":"Admin","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":1,"role_id":1}}]
[{"id":2,"role":"Korisnik","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":2,"role_id":2}}]
[{"id":2,"role":"Korisnik","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":3,"role_id":2}}]
[{"id":2,"role":"Korisnik","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":4,"role_id":2}}]
[{"id":1,"role":"Admin","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":9,"role_id":1}},{"id":2,"role":"Korisnik","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":9,"role_id":2}}]
[{"id":2,"role":"Korisnik","created_at":"2018-11-12 10:52:40","updated_at":"2018-11-12 10:52:40","pivot":{"user_id":10,"role_id":2}}]
【问题讨论】:
标签: php laravel if-statement roles