如何在另一个 python 脚本中执行 python discord bot 函数？

Question

我正在尝试创建一个 python 脚本，该脚本会在执行时使特定语音通道的用户静音。到目前为止，我可以通过在不和谐文本频道中键入命令来使所有人静音，但是当另一个 python 脚本告诉机器人时，我想使所有人静音。下面是我的尝试。

bot.py 是 python discord bot：

import discord
from discord.ext import commands
from time import sleep

client = commands.Bot(command_prefix="./")

@client.event
async def on_ready():
    print("Bot is online. ")

@client.command()
async def play_music_test():
    channel = await client.get_channel(voice_channel_number)
    voice = await channel.connect()
    await voice.play(
        discord.FFmpegPCMAudio(executable="C:/Users/USER/ffmpeg/bin/ffmpeg.exe",
                               source="C:/Users/USER/Desktop/song.mp3"))

client.run(TOKEN)

abc.py 是另一个尝试调用函数的 Python 脚本：

from bot import play_music_test
import asyncio

print("")
asyncio.run(play_music_test())

我先运行bot.py，然后尝试执行abc.py，bot 上线但执行abc.py 时，它没有打印或执行任何操作。我刚开始学习discord.py所以如果这是一个愚蠢的问题，请原谅我。

Answer 1

你可以导入它，或者将它变成一个 cog，而不是运行 python 文件 举个例子：

导入：bot.py

import discord
from discord.ext import commands
from time import sleep
from abc import *

client = commands.Bot(command_prefix="./")

@client.event
async def on_ready():
    print("Bot is online. ")

@client.command(name = "play_music", aliases = ["you can asign aliases like this", "multiple ones too"])
async def play_music_test(ctx, channel): # If the python file doesn't know what channel is, it can be asigned when calling the function in discord, think of it like sys.argv or argparse
    if channel == None: channel = ctx.channel # This sets the current channel you are in if none was provided when executing it in discord    
#    channel = await client.get_channel(channel) now you don't need this line
    voice = await channel.connect()
    await voice.play(
        discord.FFmpegPCMAudio(executable="C:/Users/USER/ffmpeg/bin/ffmpeg.exe",
                               source="C:/Users/USER/Desktop/song.mp3"))

client.run(TOKEN)

导入：abc.py remove asyncio.run(play_music_test()) 而是在不和谐中使用它！前任。 play_music_test #general

把它变成一个齿轮：bot.py

import discord
from discord.ext import commands
from time import sleep
import os

client = commands.Bot(command_prefix="./")

@client.event
async def on_ready():
    print("Bot is online. ")



for filename in os.listdir("./"):
    if filename == "bot.py": continue
    else: client.load_extension(f"cogs.{filename[:-3]}")

client.run(TOKEN)

把它变成一个齿轮：abc.py

from bot import play_music_test
import asyncio
class Mycog(commands.Cog):
    def __init__(self, client):
        self.client = client
    


    @client.command(name = "play_music", aliases = ["you can asign aliases like this", 
    "multiple ones too"])
    async def play_music_test(ctx, channel): # If the python file doesn't know what 
    channel is, it can be asigned when calling the function in discord, think of it like sys.argv or argparse
        if channel == None: channel = ctx.channel # This sets the current channel you are in if none was provided when executing it in discord    
    #    channel = await client.get_channel(channel) now you don't need this line
        voice = await channel.connect()
        await voice.play(
            discord.FFmpegPCMAudio(executable="C:/Users/USER/ffmpeg/bin/ffmpeg.exe",
                                   source="C:/Users/USER/Desktop/song.mp3"))




def setup(client):
    client.add_cog(Mycog(client))

这个anwser不是最好的，但希望这会有所帮助！

Answer 2

我不确定，如果我真的明白，你想做什么，但要从另一个脚本打开一个脚本，我使用subprocess.Popen()

但我认为，在你的情况下，它更适合改变你尝试解决问题的方式。也许您应该查看on_message 事件并使用message.content ?

Answer 3

您可以导入 client 变量 (from bot import play_music_test, client)，然后导入 client.loop.create_task(play_music_test())

（虽然我不明白你为什么要这么做）