wait_for 'reaction_add' 检查不起作用

Question

我正在执行一个命令，您需要使用表情符号确认某些内容。 我有一个 wait_for("reaction_add") 带有一个检查作为 lambda 函数。

我的以下代码是：

try:
    reaction, user = await self.client.wait_for("reaction_add",
    check=lambda react, usr: str(reaction.emoji) == "✅" and usr.id == ctx.author.id, timeout=60)
    print(reaction.emoji)
except asyncio.TimeoutError:
    await confirm_msg.edit(content="This message has timed out!", embed=None)

但它不会打印出反应表情符号。 没有检查代码可以正常工作，所以它与检查有关。我该如何解决？

谢谢！

Answer 1

你可以试试这个，不用 lambda 函数：

@client.event
async def on_raw_reaction_add(payload):
  reaction = str(payload.emoji)
  if reaction == "✅" and usr.id == ctx.author.id:
     print('do something')
  else:
     print('something else')

Answer 2

try:
    reaction, user = await self.client.wait_for("reaction_add",
    check=lambda reaction, user: str(reaction.emoji) == "✅" and user.id == ctx.author.id, timeout=60)
    print(reaction.emoji)
except asyncio.TimeoutError:
    await confirm_msg.edit(content="This message has timed out!", embed=None)

Answer 3

lambda 函数本质上与普通函数相同。

你的 lambda：

lambda react, usr: str(reaction.emoji) == "✅" and usr.id == ctx.author.id

将等于定义以下函数：

# Here we are within the wait_for(reaction_add)
def f(react, usr):
    return str(reaction.emoji) == "✅" and user.id == ctx.author.id
# Rest of the code

问题是reaction_add 没有定义react 或usr。解决您的代码的方法是这样的：

reaction, user = await self.client.wait_for("reaction_add", check=lambda reaction,
user: str(reaction.emoji) == "✅" and user.id == ctx.author.id, timeout=60)