如何在 Discord py (Bot) 中处理多个反应

Question

试图让我的机器人处理对消息的多个反应。

如果我只检查一个反应，我可以得到一个这样的版本：

reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkR)

但是当我检查多个反应（如纸和剪刀）时，代码根本不起作用。

我到处寻找有关此方面的帮助，但找不到任何在 Discord 重写后的内容。

任何帮助表示赞赏！

# test rps
@bot.command()
async def test(ctx):

    eb = await getEmbed(ctx, "Rock, Paper, Scissors", "", {}, "", "Choose one:", discord.Colour.gold())

    msg = await ctx.message.channel.send(embed = eb)
    channel = msg.channel
    for emoji in ('????', '????', "✂"):
        await msg.add_reaction(emoji)

    # now check for response
    def checkR(reaction, user):
        return user == ctx.message.author and str(reaction.emoji) == '????'
    def checkP(reaction, user):
        print("in paper")
        return user == ctx.message.author and str(reaction.emoji) == '????'
    def checkS(reaction, user):
        return user == ctx.message.author and str(reaction.emoji) == '✂'

    try:
        reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkR)
        reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkP)
        reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkS)
    except asyncio.TimeoutError:
        await embed(ctx, "Game timed out.")
        return
    else:
        # we got a reaction
        await embed(ctx, "GOT A REACTION")
        await discord.Message.delete(msg)
        pass

Answer 1

感谢我一直在寻找这个 这就是我想出的。

创建消息并添加反应：

    @commands.command()
async def pageturn(self, ctx):
    guildid = str(ctx.guild.id)
    userid = str(ctx.author.id)
    previuspage = '⬅️'
    nextpage = '➡️'
    page = 1
    msg = await ctx.send(f'page{page}')
    await msg.add_reaction(previuspage)
    await msg.add_reaction(nextpage)

    def checkforreaction(reaction, user):
        return str(user.id) == userid and str(reaction.emoji) in [previuspage,nextpage]

#loops直到reaction_add超时

    loopclose = 0
    while loopclose == 0:
        try:
            reaction, user = await self.client.wait_for('reaction_add', timeout=5,check = checkforreaction)
            if reaction.emoji == nextpage:
                page += 1
            elif reaction.emoji == previuspage:
                page-= 1
            await msg.edit(content=f'page{page}')

        except asyncio.TimeoutError:
           await ctx.send('timeout')
           loopclose = 1

Answer 2

reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkR)
reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkP)
reaction, user = await bot.wait_for('reaction_add', timeout=5, check=checkS)

这等待有人按照 Rock、Paper、Scissor 的顺序做出反应。它不仅接受纸，也不接受剪刀。它需要所有 3 个反应并按此顺序。

你需要这样写：

def check(reaction, user):
  return user == ctx.message.author and str(reaction.emoji) in ['?', '?', '✂']

reaction, user = await bot.wait_for('reaction_add', timeout=5, check=check)

这将寻找一种反应，即石头、纸或剪刀。