【发布时间】:2019-12-31 02:00:52
【问题描述】:
我在尝试连接两个层的结果时遇到错误消息。
def cnn_model_fn(learning_rate):
"""Model function for CNN."""
model1=Sequential()
# Convolutional Layer #1
model1.add(tf.keras.layers.Conv2D(
filters=20,
kernel_size=[10, 1],
kernel_initializer='he_uniform',
bias_initializer=keras.initializers.Constant(value=0),
padding="same",
activation=tf.nn.relu, input_shape=(410,1,3)))
model1.add(Flatten())
model2=Sequential()
model2.add(tf.keras.layers.Conv2D(
filters=20,
kernel_size=[10, 1],
kernel_initializer='he_uniform',
bias_initializer=keras.initializers.Constant(value=0),
padding="same",
activation=tf.nn.relu, input_shape=(410,1,3)))
model2.add(Flatten())
model4=Sequential()
model4.add(keras.layers.Concatenate(axis=-1)([model1, model2]))
optimizer = tf.train.AdamOptimizer(learning_rate)
model4.compile(loss='mean_squared_error',
optimizer=optimizer,
metrics=['mean_absolute_error', 'mean_squared_error'])
return model4
model4=cnn_model_fn(0.1)
model4.summary()
"/usr/local/lib/python3.6/site-packages/tensorflow/python/keras/layers/merge.py 在构建(自我,输入形状) 377 # 纯粹用于形状验证。 378 如果不是 isinstance(input_shape, list) 或 len(input_shape) 379 raise ValueError('A
Concatenate层应该被调用' 380 '在至少 2 个输入的列表中') 381 if all([shape is None for shape in input_shape]):ValueError: A
Concatenate层应该在列表中调用 at 至少 2 个输入"
【问题讨论】:
-
将此行 model4.add(keras.layers.Concatenate(axis=-1)([model1, model2])) 更改为 model4.add(keras.layers.concatenate(axis=-1) ([model1.output, model2.output]))
-
谢谢。它引发了另一个错误:“TypeError:添加的层必须是类 Layer 的实例。找到:Tensor("concatenate_20/concat:0", shape=(?, 16400), dtype=float32)"
标签: python tensorflow keras concatenation conv-neural-network