从渐变维度类型 II 中选择

Question

我在选择缓慢变化的维度类型 II 时遇到问题。我希望选择员工技能认证的实际长度，以便我可以在报告中显示他的认证的开始和结束。你会怎么做呢？下面我包含了员工“80844”的记录图像，记录下方是预期结果。

我正在使用 Microsoft SQL Server 2008 R2。

Answer 1

感谢您提出有趣的问题。这是众所周知的“差距和岛屿”问题。你可以阅读更多关于它的信息there。

您的案例解决方案可能如下所示：

    create table #tmp 
       (
         dimEmployeeID int not null,
         EmployeeNumber int not null,
         Start datetime not null,
         [End] datetime not null,
         SkillID int not null
       )


   insert into #tmp values
     (386 , 80844, '1900-01-01', '2012-02-28', 14),
     (1172, 80844, '2012-02-29', '2012-02-29', 14),
     (1173, 80844, '2012-03-01', '2012-04-01', 14),
     (1175, 80844, '2012-04-06', '2012-04-12', 14),
     (1176, 80844, '2012-04-13', '2012-04-21', 14),
     (1172, 80844, '2012-02-29', '2012-02-29', 87),
     (1173, 80844, '2012-03-01', '2012-04-01', 87),
     (1174, 80844, '2012-04-02', '2012-04-05', 87),
     (1175, 80844, '2012-04-06', '2012-04-12', 87)

   ;with StartingPoints as
   (
     SELECT EmployeeNumber, SkillID, Start, ROW_NUMBER() OVER(partition by EmployeeNumber,    SkillID order by Start asc) AS rn
     FROM #tmp AS A
     WHERE NOT EXISTS
       (
         SELECT 1
         FROM #tmp AS B
         WHERE 
           A.EmployeeNumber = B.EmployeeNumber
           and A.SkillID = B.SkillID
           and A.Start - 1 = B.[End]
        )
   ),
   EndingPoints AS
   (
     SELECT EmployeeNumber, SkillID, [End], ROW_NUMBER() OVER(partition by EmployeeNumber,    SkillID order by Start asc) AS rn
     FROM #tmp AS A
     WHERE NOT EXISTS
       (
         SELECT 1
         FROM #tmp AS B
         WHERE 
           A.EmployeeNumber = B.EmployeeNumber
           and A.SkillID = B.SkillID
           and A.[End] + 1 = B.Start
        )
   )
   SELECT S.EmployeeNumber, S.SkillID, S.Start, E.[End]
   FROM StartingPoints AS S
     JOIN EndingPoints AS E
   ON 
     S.EmployeeNumber = E.EmployeeNumber
     and S.SkillID = E.SkillID
     and S.rn = E.rn