如何使用php从具有多个表的mysql数据库中检索大量数据

Question

我需要特定部门的月度出勤报告。在我的程序中，生成需要更多时间。如果超过 50 名员工，则根本不会生成报告。

我有两张表，一张是员工表，另一张是出勤表。

我正在生成这样的报告。

这是我的代码。

<div class="row">
    <div class="col-md-12">   
        <table style="width:100%;" border="1">                                
            <tr style="font-weight: bold; background-color: #D3D3D3; text-align: center;">
                <td style="text-align: center;padding: 5px;">
SLNo.
                </td>   
                <td>EMPID</td>
                <td style="width:250px; text-align: center; padding-left: 5px; padding-right: 5px;">
                    Employee&nbsp;Name
                </td>

                <?php
                /* Default Date Indexing starts here. */
                $timezone = "Asia/Calcutta";
                date_default_timezone_set($timezone);
                $timestamp = mktime(0,0,0,$Month,1,$Year);
                $maxday = date("t",$timestamp);

                //echo "<td></td>";
                for ($k=1; $k<= $maxday; $k++) {  
                    $kv = sprintf('%02d', $k);
                    echo "<td style=''>$kv</td>";  
                }

                /* Default Date Indexing ends here. */
                ?>
                <td>TOT.P</td>
                <td>TOT.HLF</td>
                <td>TOT.A</td>
                <td>TOT.WO</td>
                <td>TOT.HLD</td>
            </tr>
            <?php

            //Getting all employee details according roster assign table.
            $sqlRA = "SELECT * from employee_details where DivisionDbKey = '$DivisionDbKey' and Status='ACTIVE' ORDER BY EmployeeName ASC";
            $resultRA = mysqli_query($conn, $sqlRA);
            $i = 1;
            while ($rowRA = mysqli_fetch_array($resultRA, MYSQLI_ASSOC)) {
                $EmployeeDbKey = $rowRA['DbKey'];
                $EmployeeId = $rowRA['EmployeeId'];
                $EmployeeName = $rowRA['EmployeeName'];                                                                        
                echo "<tr>";
                echo "<td style='text-align:center;'>$i</td>";
                echo "<td style='width:200px;'>$EmployeeId</td>";
                echo "<td>$EmployeeName</td>";
                $PCount = 0;$ACount = 0;$HLFCount = 0;$WOCount=0;$HLDCount=0;
                for ($kk=1; $kk<= $maxday; $kk++) {  
                    $kkv = sprintf('%02d', $kk);
                    $CurrentOPDate = $kkv."/".$Month."/".$Year; 

                    $sqlRAD = "SELECT * from employee_attendance where EmployeeDbKey = '$EmployeeDbKey' and Date ='$CurrentOPDate' and Status='ACTIVE'";
                    $resultRAD = mysqli_query($conn, $sqlRAD);
                    $rowcountRAD = mysqli_num_rows($resultRAD);
                    if ($rowcountRAD != 0) {
                        while ($rowRAD = mysqli_fetch_array($resultRAD, MYSQLI_ASSOC)) {
                            $Attendance = $rowRAD['Attendance'];                                                                                   

                            $colorcode="";
                            if($Attendance == "P" || $Attendance == "p"){
                               $PCount = $PCount + 1;
                               $colorcode = "background-color:#00C0EF; color:#FFF;"; 
                            }                                                                                    
                            elseif ($Attendance == "WO" || $Attendance == "wo" || $Attendance == "Wo") {
                                 $WOCount = $WOCount + 1;
                                $colorcode = "background-color:#2980B9; color:#FFF;";
                            }
                            elseif ($Attendance =="HLD" || $Attendance =="hld" || $Attendance == 'Hld') {
                                $HLDCount = $HLDCount + 1;
                                $colorcode = "background-color:#FFD455;color:#000;";
                            }
                            elseif ($Attendance == "HLF" || $Attendance == "hlf" || $Attendance == "Hlf") {
                                $HLFCount = $HLFCount + 1;
                                $colorcode = "background-color:#931336; color:#FFF;";
                            } 
                            elseif ($Attendance == "A" || $Attendance == "a") {
                                $ACount = $ACount + 1;
                                $colorcode = "background-color:#F00; color:#FFF;";
                            } 
                            else {

                            }

                            echo "<td style='text-align:center;font-weight:bold;$colorcode' title=''>$Attendance</td>";
                        }
                    }
                    else{
                        $ACount = $ACount + 1;
                        $colorcode = "background-color:#F00; color:#FFF;";
                        echo "<td style='text-align:center;font-weight:bold;$colorcode'>A</td>";
                    }

                }
                ?>                                                              
                <td style="text-align: center;font-weight: bold;color:#F00;"><?php echo $PCount; ?></td>
                <td style="text-align: center;font-weight: bold;color:#F00;"><?php echo $HLFCount; ?></td>
                <td style="text-align: center;font-weight: bold;color:#F00;"><?php echo $ACount; ?></td>
                <td style="text-align: center;font-weight: bold;color:#F00;"><?php echo $WOCount; ?></td>
                <td style="text-align: center;font-weight: bold;color:#F00;"><?php echo $HLDCount; ?></td>                                            
                <?php
                echo "</tr>";                                                                       
                $i = $i + 1;
            }        
            ?>
        </table> 
    </div>
</div>

请指导我该怎么做，以便我能快速掌握更多员工数据。我必须一次显示 1000 名员工的记录。

Answer 1

您应该连接这些表并对所有员工和一个月中的所有日期进行一次查询，而不是对每个员工和日期进行单独的查询。

SELECT e.EmployeeId, e.EmployeeName, a.Date, a.Attendance
FROM employee_details AS e
JOIN employee_attendance AS a ON a.EmployeeDbKey = e.DbKey
WHERE e.DivisionDbKey = '$DivisionDbKey' and e.Status='ACTIVE'
AND a.Date BETWEEN '$Year-$Month-01' AND LAST_DAY('$Year-$Month-01') and a.Status='ACTIVE'
ORDER BY e.EmployeeName, a.Date

然后，当您显示表格时，只要$row['EmployeeId'] 发生变化，就开始一个新的<tr>。

此外，当您循环查看某个员工的月份日期时，请从当前日期中减去上一个日期。如果差值大于 1，则在行中插入 $difference - 1 <td>A</td> 列以显示缺勤情况。

或查看generate days from date range。您可以使用其中一种技术来创建一个子查询，以生成该月中的所有日期。用这个左加入employee_attendance 表，你会得到每一天的行，但如果他们不存在，a.Attendance 将是NULL。