我更喜欢@胡安的解决方案,但只是为了好玩,这是一种略微不同的方法。从左上角开始的白色填充溢出,您的完全封闭的像素将全部留下。
#!/usr/bin/env python3
import numpy as np
from skimage.segmentation import flood_fill
import cv2
im = cv2.imread('scan.png', cv2.IMREAD_GRAYSCALE)
# Fill with white from top-left
filled = flood_fill(im, (0, 0), 255)
# Save result
cv2.imwrite('DEBUG-result.png', filled)
# Get list of black pixels
blk = np.where(filled==0)
print(f'Number of fully enclosed black pixels: {len(blk[0])}')
print(blk)
让您可以看到图像的范围,我人为地添加了一个红色边框:
这是输出:
Number of fully enclosed black pixels: 957
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393, 393, 393, 393, 393, 393, 393, 394, 394, 394, 394, 394, 394,
394, 394, 394, 394, 394, 394, 394, 394, 394, 395, 395, 395, 395,
395, 395, 395, 395, 395, 395, 395, 395, 395, 395, 395, 396, 396,
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397, 397, 397, 398, 398, 398, 398, 398, 398, 398, 398, 398, 399,
399, 399, 400, 400, 400, 401, 401, 401]), array([244, 245, 246, 247, 248, 249, 250, 251, 252, 253, 254, 255, 256,
257, 258, 259, 260, 261, 262, 263, 264, 265, 266, 267, 268, 269,
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276, 244, 245, 246, 247, 248, 249, 250, 251, 252, 253, 254, 255,
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265, 266, 267, 268, 269, 270, 271, 272, 273, 259, 260, 261, 262,
263, 264, 265, 266, 267, 268, 269, 270, 271, 272, 273, 262, 263,
264, 265, 266, 267, 268, 269, 270, 262, 263, 264, 265, 266, 267,
268, 269, 270, 262, 263, 264, 265, 266, 267, 268, 269, 270, 265,
266, 267, 265, 266, 267, 265, 266, 267]))
希望您可以从每个阵列的第一个元素看,第一个黑色像素是364,244
请注意,如果扫描将触摸图像的边缘有可能触摸图像的边缘,则洪水填充将无法在边缘周围的所有方式“流” em>。在这种情况下,您可以简单地添加一个围绕边缘的1像素宽黑色边框,以便填充填充物流......然后将其移除。