【发布时间】:2021-01-14 00:02:02
【问题描述】:
我正在尝试解决利润最大化问题。该公司有一些促销计划。我为利润最大化制定了一个目标函数,但受到一些约束。我想提出一个限制条件,即公司不能同时运行超过 2 个促销计划。但是这种情况不起作用
这是我的代码:
from scipy.optimize import minimize
from math import floor
#Objective function
def objective(x):
return -((-14.12*x[0]+1*floor(x[1])+2*floor(x[2])+4*floor(x[3]))*x[0] \ #total revenue (qty*price)
-(-14.12*x[0]+1*floor(x[1])+2*floor(x[2])+4*floor(x[3]))*10000*0.05\ #Gold price cost
-(-14.12*x[0]+1*floor(x[1])+2*floor(x[2])+4*floor(x[3]))*x[0]*0.1\ #Rebate cost
-(-14.12*x[0]+1*floor(x[1])+2*floor(x[2])+4*floor(x[3])/15000*100000))
#Points constraint
#Constraints
def PriceConstraint(x):
return x[0]-3000
def GoldCoinConstraint(x):
return floor(x[1])-1
def PointsConstraint(x):
return floor(x[2])-1
def ProgressiveRebateConstraint(x):
return floor(x[3])-1
def CombinationConstraint(x):
return 2-floor(x[1])+floor(x[2])+floor(x[3])
#Initial guesses
n=5
x0=np.zeros(5)
x0[0]=1
x0[1]=2
x0[2]=2
x0[3]=1
x0[4]=3
# show initial objective
print('Initial Objective: ' + str(objective(x0)))
# optimize
b = (0.0,1.0)
pricebound = (1,3000)
bnds = (pricebound, b, b, b,b)
con1= {'type':'ineq','fun':PriceConstraint}
con2= {'type':'ineq','fun':GoldCoinConstraint}
con3= {'type':'ineq','fun':PointsConstraint}
con4= {'type':'ineq','fun':ProgressiveRebateConstraint}
con5= {'type':'ineq','fun':CombinationConstraint}
cons = ([con1, con2, con3, con4, con5])
solution = minimize(objective,x0,method='SLSQP',\
bounds=bnds,constraints=cons)
x = solution.x
# show final objective
print('Final Objective: ' + str(objective(x)))
# print solution
print('Solution')
print('x1 = ' + str(x[0]))
print('x2 = ' + str(x[1]))
print('x3 = ' + str(x[2]))
print('x4 = ' + str(x[3]))
如您所见,我使用combinationconstrain 函数设置了营销方案的数量不应超过2 个的约束。不知何故,它似乎不起作用?我得到 x[1]、x[2] 和 x[3] 的输出为 1。
有人能帮我解释一下为什么这不起作用吗?
另外一种思路是非线性优化中的影子价格。我知道它存在于线性规划中,但不确定非线性?
【问题讨论】:
标签: python optimization scipy-optimize scipy-optimize-minimize