【发布时间】:2012-09-25 02:29:16
【问题描述】:
我有以下10折实现,我使用UCI Machine learning发布的数据集,这是数据集的链接:
Here are my dimensions
x =
data: [178x13 double]
labels: [178x1 double]
这是我遇到的错误
Index exceeds matrix dimensions.
Error in GetTenFold (line 33)
results_cell{i,2} = shuffledMatrix(testRows ,:);
这是我的代码:
%Function that accept data file as a name and the number of folds
%For the cross fold
function [results_cell] = GetTenFold(dataFile, x)
%loading the data file
dataMatrix = load(dataFile);
%combine the data and labels as one matrix
X = [dataMatrix.data dataMatrix.labels];
%geting the length of the of matrix
dataRowNumber = length(dataMatrix.data);
%shuffle the matrix while keeping rows intact
shuffledMatrix = X(randperm(size(X,1)),:);
crossValidationFolds = x;
%Assinging number of rows per fold
numberOfRowsPerFold = dataRowNumber / crossValidationFolds;
crossValidationTrainData = [];
crossValidationTestData = [];
%Assigning 10X2 cell to hold each fold as training and test data
results_cell = cell(10,2);
%starting from the first row and segment it based on folds
i = 1;
for startOfRow = 1:numberOfRowsPerFold:dataRowNumber
testRows = startOfRow:startOfRow+numberOfRowsPerFold-1;
if (startOfRow == 1)
trainRows = (max(testRows)+1:dataRowNumber);
else
trainRows = [1:startOfRow-1 max(testRows)+1:dataRowNumber];
i = i + 1;
end
%for i=1:10
results_cell{i,1} = shuffledMatrix(trainRows ,:);
results_cell{i,2} = shuffledMatrix(testRows ,:); %This is where I am getting my dimension error
%end
%crossValidationTrainData = [crossValidationTrainData ; shuffledMatrix(trainRows ,:)];
%crossValidationTestData = [crossValidationTestData ;shuffledMatrix(testRows ,:)];
end
end
【问题讨论】:
-
与其给你提供任何答案,我认为给你一些关于如何自己解决这个问题的建议要好得多。学习使用调试器。在 Matlab 命令提示符下键入
dbstop if error。这将导致 Matlab 在发生错误时进入调试器。在调试器中,您在函数内部,可以访问其中定义的所有变量。因此,在调试器中,键入max(testRows)和size(shuffledMatrix,1)之类的内容。这已经告诉你出了什么问题。输入dbcont尝试继续,或输入dbquit退出调试器。 -
谢谢我是数学实验室的新手,但我不知道当我在另一个 150 X 4 的数据集上运行它时,它没有任何问题。
标签: matlab matrix machine-learning dimension