python，改变矩阵眼的值[关闭]

Question

我有如下的python代码

import numpy as np

II = np.eye(3, 3, k=-1)
II[0,0] = 0
II[0,1] = 0
print(II)

得到结果

[[ 0.  0.  0.]
 [ 1.  0.  0.]
 [ 0.  1.  0.]]

我想要的预期结果是

 [[ 0.  0.  0.]
 [ -1.  1.  0.]
 [ 0.  -1.  1.]]

我该如何解决？

Answer 1

您可以执行以下操作。

import numpy as np

A = np.eye(3, 3)
B = np.eye(3, 3, k=-1)
B[B>0]=-1
C = A + B
C[0, 0] = 0
print(C)

输出：

[[ 0.  0.  0.]
 [-1.  1.  0.]
 [ 0. -1.  1.]]