【问题标题】:How to split data with leave one pair out cross validation (LeavePOut) for binary classification?如何通过保留一对交叉验证(LeavePOut)来拆分数据以进行二进制分类?
【发布时间】:2020-12-21 14:12:08
【问题描述】:

我想在二元分类问题上应用离开一对交叉验证 (LPOCV)。对于被选为保持/测试对的每一对样本,它应该是每个二元类中的一个样本。

我的代码是这样的:

from sklearn.model_selection import LeavePOut
import numpy as np
X = np.array([[1, 2], [3, 4], [5, 6], [7, 8],[9,10]])
y = np.array([0,1,1,0,0])
lpo = LeavePOut(2)
print(lpo.get_n_splits(X))

print(lpo)
LeavePOut(p=2)
for train_index, test_index in lpo.split(X):
  print("TRAIN:", train_index, "TEST:", test_index)
  X_train, X_test = X[train_index], X[test_index]
  y_train, y_test = y[train_index], y[test_index]

输出如下:

LeavePOut(p=2)
TRAIN: [2 3 4] TEST: [0 1]
TRAIN: [1 3 4] TEST: [0 2]
TRAIN: [1 2 4] TEST: [0 3]
TRAIN: [1 2 3] TEST: [0 4]
TRAIN: [0 3 4] TEST: [1 2]
TRAIN: [0 2 4] TEST: [1 3]
TRAIN: [0 2 3] TEST: [1 4]
TRAIN: [0 1 4] TEST: [2 3]
TRAIN: [0 1 3] TEST: [2 4]
TRAIN: [0 1 2] TEST: [3 4]

测试对[0 3][0 4]属于同一类0。他们有什么方法可以将 X 数据与包含 0 类和 1 类样本的测试对分开吗?

【问题讨论】:

    标签: python-3.x scikit-learn cross-validation


    【解决方案1】:

    我认为您可以调整您的代码,以便省略测试集仅包含一个类(例如类 0)的索引的所有折叠:

    from sklearn.model_selection import LeavePOut
    import numpy as np
    X = np.array([[1, 2], [3, 4], [5, 6], [7, 8],[9,10]])
    y = np.array([0,1,1,0,0])
    lpo = LeavePOut(2)
    print(lpo.get_n_splits(X))
    
    print(lpo)
    LeavePOut(p=2)
    for train_index, test_index in lpo.split(X):
        for x in range(0,len(test_index)):
          for z in range(1,len(test_index)):
            if(y[test_index[x]] != y[test_index[z]]):
              print("TRAIN:", train_index, "TEST:", test_index)
              X_train, X_test = X[train_index], X[test_index]
              y_train, y_test = y[train_index], y[test_index]
    

    那么输出是:

    LeavePOut(p=2)
    TRAIN: [2 3 4] TEST: [0 1]
    TRAIN: [1 3 4] TEST: [0 2]
    TRAIN: [0 2 4] TEST: [1 3]
    TRAIN: [0 2 3] TEST: [1 4]
    TRAIN: [0 1 4] TEST: [2 3]
    TRAIN: [0 1 3] TEST: [2 4]
    

    删除的折叠是测试集仅代表一个类别的折叠,即 [0 3][0 4] >[1 2][3 4]

    【讨论】:

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