我认为问题是您的第一个数据行设置为列名。
因此需要将 header=0 更改为 header=None 以获取默认的 RangeIndex 列名称。
import pandas as pd
temp=u"""1,2268318,2520377,pv,1511544070
1,2333346,2520771,pv,1511561733
1,2576651,149192,pv,1511572885
1,3830808,4181361,pv,1511593493
1,4365585,2520377,pv,1511596146
1,4606018,2735466,pv,1511616481"""
#after testing replace 'pd.compat.StringIO(temp)' to 'filename.csv'
df = pd.read_csv(pd.compat.StringIO(temp), header=None)
print (df)
0 1 2 3 4
0 1 2268318 2520377 pv 1511544070
1 1 2333346 2520771 pv 1511561733
2 1 2576651 149192 pv 1511572885
3 1 3830808 4181361 pv 1511593493
4 1 4365585 2520377 pv 1511596146
5 1 4606018 2735466 pv 1511616481
额外的第一列称为索引,如果需要删除它,如果将DataFrame 写入csv 使用参数index=False 并删除列名称header=None:
df.to_csv(file, index=False, header=None)
1,2268318,2520377,pv,1511544070
1,2333346,2520771,pv,1511561733
1,2576651,149192,pv,1511572885
1,3830808,4181361,pv,1511593493
1,4365585,2520377,pv,1511596146
1,4606018,2735466,pv,1511616481
编辑:
我建议创建自定义列名称,以便通过参数names 更轻松地处理数据(header=None 不是必需的)并删除某些列使用drop:
import pandas as pd
temp=u"""1,2268318,2520377,pv,1511544070
1,2333346,2520771,pv,1511561733
1,2576651,149192,pv,1511572885
1,3830808,4181361,pv,1511593493
1,4365585,2520377,pv,1511596146
1,4606018,2735466,pv,1511616481"""
#after testing replace 'pd.compat.StringIO(temp)' to 'filename.csv'
df = pd.read_csv(pd.compat.StringIO(temp), names=['col1','col2','col3','col4','col5'])
print (df)
col1 col2 col3 col4 col5
0 1 2268318 2520377 pv 1511544070
1 1 2333346 2520771 pv 1511561733
2 1 2576651 149192 pv 1511572885
3 1 3830808 4181361 pv 1511593493
4 1 4365585 2520377 pv 1511596146
5 1 4606018 2735466 pv 1511616481
df1 = df.drop('col4', axis=1)
print (df1)
col1 col2 col3 col5
0 1 2268318 2520377 1511544070
1 1 2333346 2520771 1511561733
2 1 2576651 149192 1511572885
3 1 3830808 4181361 1511593493
4 1 4365585 2520377 1511596146
5 1 4606018 2735466 1511616481