【发布时间】:2019-05-12 23:08:14
【问题描述】:
我的 python 代码最初输出了这些结果,一个人口普查区(基本上是一块土地)人口的字典列表和各种土地覆盖类型。这里是:
[{'Total Population:': 4585, 'Total Water Ice Cover': 2.848142234497044, 'Total Developed': 17.205368316575324, 'Total Barren Land': 0.22439908514219134, 'Total Forest': 34.40642126612868},
{'Total Population:': 4751, 'Total Water Ice Cover': 1.047783534830167, 'Total Developed': 37.27115716753022, 'Total Barren Land': 0.11514104778353484, 'Total Forest': 19.11341393206678},
{'Total Population:': 3214, 'Total Water Ice Cover': 0.09166603009701321, 'Total Developed': 23.50469788404247, 'Total Barren Land': 0.2597204186082041, 'Total Forest': 20.418608204109695},
{'Total Population:': 5005, 'Total Water Ice Cover': 0.0, 'Total Developed': 66.37545713124746, 'Total Barren Land': 0.0, 'Total Forest': 10.68671271840715},
...
]
然后将该代码放入熊猫对象中:
import pandas as pd
df = pd.DataFrame(output)
print(df)
# Total Barren Land Total Developed Total Forest Total Population: Total Water Ice Cover
#0 0.224399 17.205368 34.406421 4585 2.848142
#1 0.115141 37.271157 19.113414 4751 1.047784
#2 0.259720 23.504698 20.418608 3214 0.091666
#3 0.000000 66.375457 10.686713 5005 1.047784
然后得到 pearson 'r' 相关性:
pd.set_option("precision",4) # only show 4 digits
# remove 'Total ' from column names to make printing smaller
df.rename(columns=lambda x: x.replace("Total ", ""), inplace=True)
corr = df.corr(method="pearson")
print(corr)
# Barren Land Developed Forest Population: Water Ice Cover
#Barren Land 1.0000 -0.9579 0.7361 -0.7772 0.4001
#Developed -0.9579 1.0000 -0.8693 0.5736 -0.6194
#Forest 0.7361 -0.8693 1.0000 -0.1575 0.9114
#Population: -0.7772 0.5736 -0.1575 1.0000 0.2612
#Water Ice Cover 0.4001 -0.6194 0.9114 0.2612 1.0000
现在我有了人口和各种土地覆盖类型之间的所有 pearson 'r' 相关值。
我现在要做的是计算多元线性回归。我正在尝试在以下表面覆盖的人口密度和面积百分比之间执行多元线性回归,并计算回归的 R2:发达、种植/栽培类,也许还有其他一些。这也可以通过 pandas 来完成吗?
谢谢
【问题讨论】:
标签: python pandas scikit-learn linear-regression