【发布时间】:2020-12-07 08:06:56
【问题描述】:
我正在使用 from sklearn.preprocessing import MinMaxScaler 使用以下代码和数据集:
df = pd.DataFrame({
"A" : [-0.5624105,
-0.5637749,
0.2973856,
0.619784,
0.007297921,
0.8146919,
0.1082434,
-0.2311236,
-0.6945567,
-0.6807524,
-0.1017431,
0.5889628,
0.5384794,
0.3906553,
0.3843442,
0.4408366,
0.4035791,
0.05258237,
-0.4847771
],
"B" : [-0.5068743,
0.1422121,
0.6444226,
0.4959088,
-0.2260773,
0.3420533,
0.2346546,
0.1177824,
-0.7701161,
-0.7566853,
-0.5091485,
0.4509938,
0.4209853,
0.304058,
0.3753832,
0.6958977,
0.6763205,
0.05536954,
-0.9857719
]})
min_max_scaler = MinMaxScaler(feature_range=(0,255))
print(df)
df[df.columns] = min_max_scaler.fit_transform(df[df.columns])
print(df)
print(type(df))
我想用整个数据集中的最小值和整个数据集中的最大值来缩放它如何使用相同的代码来管理它?有可能吗?
A B
0 -0.562411 -0.506874
1 -0.563775 0.142212
2 0.297386 0.644423
3 0.619784 0.495909
4 0.007298 -0.226077
5 0.814692 0.342053
6 0.108243 0.234655
7 -0.231124 0.117782
8 -0.694557 -0.770116
9 -0.680752 -0.756685
10 -0.101743 -0.509149
11 0.588963 0.450994
12 0.538479 0.420985
13 0.390655 0.304058
14 0.384344 0.375383
15 0.440837 0.695898
16 0.403579 0.676320
17 0.052582 0.055370
18 -0.484777 -0.985772
A B
0 22.327190 72.617646
1 22.096664 171.041874
2 167.596834 247.194572
3 222.068703 224.674680
4 118.584127 115.196304
5 255.000000 201.344798
6 135.639699 185.059394
7 78.300845 167.337476
8 0.000000 32.700971
9 2.332350 34.737551
10 100.160748 72.272798
11 216.861207 217.863993
12 208.331620 213.313653
13 183.355519 195.583380
14 182.289206 206.398778
15 191.834063 255.000000
16 185.539101 252.031411
17 126.235309 157.873501
18 35.443994 0.000000
我不想为每一列使用不同的映射,我需要使用 -0.985772 0.814692 进行映射(第 18 列 b 行,第 5 行第 a 列)
【问题讨论】:
-
首先将其设为
np.array,然后将其设为array = (array - minimum) / (maximum - minimum) * 255(从 0 到 255)然后再转换回可能是最快的
标签: python pandas dataframe sklearn-pandas