MySQL选择给定日期位于存储在表中的日期之间的行

Question

假设我有一些数据，例如：

id  status activity_date
--- ------ -------------
101   R     2014-01-12
101   Mt    2014-04-27 
101   R     2014-05-18
102   R     2014-02-19

请注意，对于 id = 101 的行，我们在 2014-01-12 到 2014-04-26 和 2014-05-18 到当前日期之间有活动。

现在我需要选择 status = 'R' 并且日期是给定日期的最新日期的数据，例如如果我搜索 2014-02-02，我会找到在 2014-01-12 创建的状态行，因为该状态在当时对于实体 ID 101 仍然有效。

Answer 1

试试这个：

select * from yourtable 
where status='R' and activity_date= '2014-02-02'

Answer 2

你可以试试

select id, status, activity_date 
from TABLE 
where status = "R" and activity_date = "2014-02-02"

其中 TABLE 是您的表的名称

Answer 3

我认为你需要关注 ans

SELECT id,MAX(CAST(ACTIVITY_DATE AS date),MIN(CAST (ACTIVITY_DATE AS date)  
FROM Table_Name WHERE CAST('2014-02-02' AS date)
BETWEEN  MIN(CAST (ACTIVITY_DATE AS date) AND MAX(CAST(ACTIVITY_DATE AS date) 
 AND Status='R'
GROUP BY id

Answer 4

试试下面的

SELECT *
FROM your_relation
WHERE status='R'
AND activity_data="2014-02-02"

Answer 5

如果我理解正确：

第 1 步：将开始日期和结束日期行转换为列。为此，您必须根据此条件将表与自身连接：

SELECT
    dates_fr.id,
    dates_fr.activity_date AS date_fr,
    MIN(dates_to.activity_date) AS date_to
FROM test AS dates_fr
LEFT JOIN test AS dates_to ON 
    dates_to.id = dates_fr.id AND
    dates_to.status = 'Mt' AND
    dates_to.activity_date > dates_fr.activity_date
WHERE dates_fr.status = 'R'
GROUP BY dates_fr.id, dates_fr.activity_date

+------+------------+------------+
| id   | date_fr    | date_to    |
+------+------------+------------+
|  101 | 2014-01-12 | 2014-04-27 |
|  101 | 2014-05-18 | NULL       |
|  102 | 2014-02-19 | NULL       |
+------+------------+------------+

第 2 步：剩下的很简单。将查询包装在另一个查询中并使用适当的 where 子句：

SELECT * FROM (
    SELECT
        dates_fr.id,
        dates_fr.activity_date AS date_fr,
        MIN(dates_to.activity_date) AS date_to
    FROM test AS dates_fr
    LEFT JOIN test AS dates_to ON 
        dates_to.id = dates_fr.id AND
        dates_to.status = 'Mt' AND
        dates_to.activity_date > dates_fr.activity_date
    WHERE dates_fr.status = 'R'
    GROUP BY dates_fr.id, dates_fr.activity_date
) AS temp WHERE '2014-02-02' >= temp.date_fr and ('2014-02-02' < temp.date_to OR temp.date_to IS NULL)

+------+------------+------------+
| id   | date_fr    | date_to    |
+------+------------+------------+
|  101 | 2014-01-12 | 2014-04-27 |
+------+------------+------------+

SQL Fiddle

Answer 6

我完全同意 Salman 的回答，该表的设计方式可以提高查询的准确性和可扩展性。但是，关于基于状态和日期范围的查询选择信息的问题可以表示为。

SELECT * FROM Table_1
WHERE ((status = 'R')
AND ((activity_date BETWEEN '2014-01-12' AND '2014-04-26')
OR activity_date  > CONVERT(DATETIME, '2014-05-17')))

这将选择状态为“R”的所有数据，并将使用 BETWEEN 运算符获取所需范围；另外，final 运算符的转换是因为表达式作为数学表达式求值，需要显式转换。

Answer 7

您可以进行查询以有效地为您提供截至日期的最多状态，例如

SELECT
    id, 
    substr(max(concat(activity_date, status)),11) as status,
    max(activity_date) as activity_date
FROM table
WHERE activity_date <= '2014-02-02'
GROUP by id;

然后，类似于 Salman 的回答，您可以在另一个查询中使用此结果并查找所有状态为“R”的结果

SELECT * from (
    SELECT
        id,
        substr(max(concat(activity_date, status)),11) as status,
        max(activity_date) as activity_date
    FROM table
    WHERE activity_date <= '2014-02-02'
    GROUP by id
) AS temp WHERE temp.status = 'R';

编辑：您可以使用子查询来识别相关的最大记录，而不是使用有问题的状态排序方法，因此原始查询将变为

SELECT join1.* FROM table AS join1
INNER JOIN (
    SELECT id, max(activity_date) as max_activity_date
    FROM table
    WHERE activity_date < '2014-02-02'
    GROUP BY id
) AS join2
ON join1.id = join2.id AND join1.activity_date = join2.max_activity_date;

以及完整的查询

SELECT * from (
    SELECT join1.* FROM table AS join1
    INNER JOIN (
        SELECT id, max(activity_date) as max_activity_date
        FROM table
        WHERE activity_date < '2014-02-02'
        GROUP BY id
    ) AS join2
    ON join1.id = join2.id AND join1.activity_date = join2.max_activity_date
) AS temp WHERE temp.status = 'R';