Python Pandas - 遍历 Excel 文件的文件夹，将每个 Excel 文件工作表中的数据导出到它们自己的 .xlsx 文件中

Question

我有一个 Excel 文件文件夹，其中许多有 3-4 个选项卡的数据，我只希望这些数据作为单独的 Excel 文件。例如，假设我有一个包含三个选项卡的 Excel 文件：“员工”、“摘要”和“数据”。我希望它从中创建 3 个新的 Excel 文件：employees.xlsx、summary.xlsx 和 data.xlsx。

我的代码将遍历文件夹并识别所有选项卡，但我一直在努力弄清楚如何将数据从每张工作表单独导出到其自己的 Excel 文件中。我已经到了可以遍历文件夹、打开每个 Excel 文件并找到每个工作表的名称的地步。这是我目前所拥有的。

import pandas as pd
import os

# filenames
files = os.listdir()    
excel_names = list(filter(lambda f: f.endswith('.xlsx'), files))

excels = [pd.ExcelFile(name, engine='openpyxl') for name in excel_names]
sh = [x.sheet_names for x in excels] # I am getting all of the sheet names here
for s in sh:
    for x in s:
        #there is where I want to start exporting each sheet as its own spreadsheet

#df.to_excel("output.xlsx", header=False, index=False) #I want to eventually export it obviously, this is a placeholder

Answer 1

import pandas as pd
import glob

# get the file names using glob 
# (this assumes that the files are in the current working directory)
excel_names = glob.glob('*.xlsx')
# iterate through the excel file names
for excel in excel_names:
    # read the excel file with sheet_name as none
    # this will create a dict
    dfs = pd.read_excel(excel, sheet_name=None)
    # iterate over the dict keys (which is the sheet name)
    for key in dfs.keys():
        # use f-strings (only available in python 3) to assign 
        # the new file name as the sheet_name
        dfs[key].to_excel(f'{key}.xlsx', index=False)