用每个点上的标签可视化散点图答案

【问题标题】：Visualize scatter plot with labels on each point用每个点上的标签可视化散点图
【发布时间】：2021-09-10 23:15:36
【问题描述】：

我有一个数据集经度、纬度、城市以及冠状病毒城市的状态。我想在每个点上为城市名称贴上标签。我不知道我是否一一使用 plt.text() 来给出标签。这是我用于创建数据集的代码

jabar = [
['Depok',-6.385589,106.830711,'sedang',600],
['Tasikmalaya',-7.319563,108.202972,'sedang',600],
['Ciamis',-7.3299,108.3323,'sedang',600],
['Kuningan',-7.0138,108.5701,'sedang',600],
['Bogor',-6.497641,106.828224,'sedang',600],
['Bogor',-6.595038,106.816635,'sedang',600],
['Cirebon',-6.737246,108.550659,'sedang',600],
['Majalengka',-6.8364,108.2274,'sedang',600],
['Sumedang',-6.8381,107.9275,'sedang',600],
['Indramayu',-6.327583,108.324936,'sedang',600],
['Subang',-6.571589,107.758736,'sedang',600],
['Purwakarta',-6.538681,107.449944,'sedang',600],
['Karawang',-6.3227,107.3376,'sedang',600],
['Bekasi',-6.241586,106.992416,'sedang',600],
['Pangandaran',-7.6833,108.6500,'sedang',600],
['Sukabumi',-6.923700,106.928726,'sedang',600],
['Cimahi',-6.8841,107.5413,'sedang',600],
['Banjar',-7.374585,108.558189,'sedang',600],
['Cianjur',-6.734679,107.041252,'sedang',600],
['Bandung',-6.914864,107.608238,'tinggi',1000],
['Bandung',-6.905977,107.613144,'tinggi',1000],
['Bandung',-6.914744,107.609810,'tinggi',1000],
['Garut',-7.227906,107.908699,'sedang',600],
['Bandung Barat',-7.025253,107.519760,'sedang',600]]
features=['City','longitude','latitude','status','status_size']
risk_map = pd.DataFrame(jabar, columns=features)

这是我为可视化创建的代码，用于为每个点提供标签。

import matplotlib.pyplot as plt
plt.figure(figsize=(14,8))
plt.scatter(risk_map['latitude'],risk_map['longitude'], c='orange',
s=risk_map['status_size'], label='Risk region')
plt.title('Peta Sebaran Covid-19', fontsize=20)
plt.text(-7.227906,107.908699,'Garut')
plt.show()

实际上，我有两个数据集，不包括我上面写的代码，另一个是关于确认阳性病例 covid 区域的数据，大约超过 500.000 个点。我合并这两个数据集以获得风险区域。但是当我想在每个点上加一个标签时我会遇到麻烦。我上面写的 plt.text() 是在一个点上给出标签的例子。如果我一一写和文本代码一样是不可能的，因为我的计算机在我执行该代码后被破解并空白。

任何人有任何想法给我写上面代码的每个点打一个标签吗？提前感谢

【问题讨论】：

标签： python pandas matplotlib scatter-plot

【解决方案1】：

plotly mapbox 提供非常简单易用的功能来满足您的需求
您的 longitude、latitude 值是相反的。请参阅下面的代码示例，我已将它们反转

import plotly.express as px
import pandas as pd


jabar = [
['Depok',-6.385589,106.830711,'sedang',600],
['Tasikmalaya',-7.319563,108.202972,'sedang',600],
['Ciamis',-7.3299,108.3323,'sedang',600],
['Kuningan',-7.0138,108.5701,'sedang',600],
['Bogor',-6.497641,106.828224,'sedang',600],
['Bogor',-6.595038,106.816635,'sedang',600],
['Cirebon',-6.737246,108.550659,'sedang',600],
['Majalengka',-6.8364,108.2274,'sedang',600],
['Sumedang',-6.8381,107.9275,'sedang',600],
['Indramayu',-6.327583,108.324936,'sedang',600],
['Subang',-6.571589,107.758736,'sedang',600],
['Purwakarta',-6.538681,107.449944,'sedang',600],
['Karawang',-6.3227,107.3376,'sedang',600],
['Bekasi',-6.241586,106.992416,'sedang',600],
['Pangandaran',-7.6833,108.6500,'sedang',600],
['Sukabumi',-6.923700,106.928726,'sedang',600],
['Cimahi',-6.8841,107.5413,'sedang',600],
['Banjar',-7.374585,108.558189,'sedang',600],
['Cianjur',-6.734679,107.041252,'sedang',600],
['Bandung',-6.914864,107.608238,'tinggi',1000],
['Bandung',-6.905977,107.613144,'tinggi',1000],
['Bandung',-6.914744,107.609810,'tinggi',1000],
['Garut',-7.227906,107.908699,'sedang',600],
['Bandung Barat',-7.025253,107.519760,'sedang',600]]
features=['City','longitude','latitude','status','status_size']
risk_map = pd.DataFrame(jabar, columns=features)

fig = px.scatter_mapbox(risk_map, lon="latitude", lat="longitude", 
                        color="status", hover_name="City",size="status_size"
                       )
fig.update_layout(mapbox={"style":"carto-positron"})

fig

【讨论】：