返回 NaN 的数组

Question

我在为数组分配值时遇到问题，当我稍后访问该数组槽时，它返回 NaN。

首先，我声明数组如下：

    var oldTherms = []; 
    var newTherms = [];
    var oldInputTherms;
    var newInputTherms;

我正在使用变量数据集来计算要分配给 oldTherms 和 newTherms 数组的值。我已经验证了计算部分可以正常工作，并为 oldInputTherms 和 newInputTherms 提供了适当的值。我还验证了 dataSet.month[i] 返回正确的值。但是，下面的 switch 语句似乎没有将累积总数添加到 oldTherms[] 或 newTherms[]。当我尝试访问 newTherms[] 或 oldTherms[] 时，结果是 'NaN'

switch (dataSet.month[i]){
    //subtract 1 in array slot bc months number 1-12 and array slots number 0-11
    case 1: //january
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 2: //february
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 3: //march
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 4: //april
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 5: //may
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 6: //june
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 7:  //july
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 8: //august
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 9:  //sept
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 10: //oct
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 11: //nov
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    case 12:  //dec
        oldTherms[dataSet.month[i]-1] += oldInputTherms; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += newInputTherms;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
        break;
    default:
        oldTherms[dataSet.month[i]-1] += 0; //add therms to the total used 
        newTherms[dataSet.month[i]-1] += 0;
        oldKwh[dataSet.month[i]-1] += 0; //no cooling energy calcs
        newKwh[dataSet.month[i]-1] += 0;
}

Answer 1

当我尝试访问 newTherms[] 或 oldTherms[] 时，结果是 'NaN'

oldInputTherms, newInputTherms 已声明，但未定义，所以像这样的行

oldTherms[dataSet.month[i]-1] += oldInputTherms;
newTherms[dataSet.month[i]-1] += newInputTherms; 

会导致你的 NaN。

---

但是，你说

我已验证计算部分可以正常工作，并为 oldInputTherms 和 newInputTherms 提供了适当的值

如果是这样，那么可能oldTherms 和newTherms 没有正确初始化。如果是这种情况，请参阅上面 Barmar 的回答。

Answer 2

你需要初始化数组以包​​含0：

var oldTherms = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]; 
var newTherms = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]; 

否则，您将newInputTherms 和oldInputTherms 添加到undefined，结果是NaN。