应用程序终止时 Firebase 推送通知回调不起作用

Question

所以我更新了firebase_messaging，我不得不更改我的代码，因为FirebaseMessagin.configure() 已被弃用，现在当我收到通知并单击通知时，它不会打开另一个屏幕。

这就是我实现通知的方式：

Future<void> _firebaseMessagingBackgroundHandler(RemoteMessage message) async {
  await Firebase.initializeApp();
  print('Handling a background message ${message.messageId}');
}
const AndroidNotificationChannel channel = AndroidNotificationChannel(
  'high_importance_channel', // id
  'High Importance Notifications', // title
  'This channel is used for important notifications.', // description
  importance: Importance.high,
);

final FlutterLocalNotificationsPlugin flutterLocalNotificationsPlugin =
    FlutterLocalNotificationsPlugin();
Future<void> main() async {
  WidgetsFlutterBinding.ensureInitialized();
  FirebaseMessaging.onBackgroundMessage(_firebaseMessagingBackgroundHandler);
  runApp(MyApp());
}
class MyApp extends StatelessWidget {
  const MyApp({Key key}) : super(key: key);

  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      title: 'e-Rădăuți',
      debugShowCheckedModeBanner: false,
      initialRoute: '/',
      routes: {
        '/': (_) => MenuScreen(),
        '/events': (BuildContext context) => EventsScreen(),
      },
    );
  }
}
class MenuScreen extends StatefulWidget {
  @override
  _MyAppState createState() => new _MyAppState();
}

 Widget build(BuildContext context) {
    return Scaffold();
  }

  @override
  void initState() {
    super.initState();
    FirebaseMessaging.onMessage.listen((RemoteMessage message) {
      RemoteNotification notification = message.notification;
      AndroidNotification android = message.notification?.android;
      if (notification != null && android != null) {
        flutterLocalNotificationsPlugin.show(
            notification.hashCode,
            notification.title,
            notification.body,
            NotificationDetails(
              android: AndroidNotificationDetails(
                channel.id,
                channel.name,
                channel.description,
                icon: 'launch_background',
              ),
            ));
      }
    });
    FirebaseMessaging.onMessageOpenedApp.listen((RemoteMessage message) {
      debugPrint('A new onMessageOpenedApp event was published!');
      
      Navigator.pushNamed(context, '/events');
    });
  }
}

但是当我点击通知时不会调用 .onMessageOpenedApp，因为我在控制台 (VSCode) 中没有收到 debugPrint 消息并且我收到以下错误：

D/FLTFireMsgReceiver( 4799): broadcast received for message
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->add(I)Z (greylist,test-api, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->add(ILjava/lang/String;)Z (greylist,test-api, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->get(I)I (greylist, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->getName(I)Ljava/lang/String; (greylist, reflection, allowed)
W/FirebaseMessaging( 4799): Notification Channel set in AndroidManifest.xml has not been created by the app. Default value will be used.
I/flutter ( 4799): Handling a background message 0:1617783965733220%2ebdcc762ebdcc76

我使用 click_action: FLUTTER_NOTIFICATION_CLICK 从 firebase 发送了通知，并在我的清单中添加了

<intent-filter>
 <action android:name="FLUTTER_NOTIFICATION_CLICK" />
 <category android:name="android.intent.category.DEFAULT" />
</intent-filter>

我的firebase_messaging 版本是^8.0.0-dev.15

所以我不知道我错过了什么或为什么它不起作用。如果您需要更多详细信息，请随时询问。

Answer 1

我通过使用.getInitialMessage() 函数解决了这个问题（这是应用程序终止时的回调。 当应用程序处于后台但未终止时，我的通知有效。

为了解决这个问题，我刚刚将它添加到我的代码中：

FirebaseMessaging.instance
    .getInitialMessage()
    .then((RemoteMessage message) {
  if (message != null) {
    Navigator.pushNamed(context, message.data['view']);
  }
});

我已经做了一个工作演示 here

Answer 2

当应用程序在后台时它应该可以工作，但是当它被终止时你应该使用getInitialMessage。

onMessageOpenedApp：如果应用已从后台状态打开（未终止），则会发送 Stream 事件。

如果您的应用在应用终止时通过通知打开，请参阅getInitialMessage。

查看示例：https://github.com/FirebaseExtended/flutterfire/blob/master/packages/firebase_messaging/firebase_messaging/example/lib/main.dart#L116

Answer 3

如果您想在应用启动前点击通知时转到任何页面或午餐链接，那么您必须使用

getInitialMessage()

示例：

FirebaseMessaging.instance
    .getInitialMessage()
    .then((RemoteMessage message) {
  if (message != null) {

   //to do your operation
   launch('https://google.com');

  }
});