【发布时间】:2014-07-26 15:48:47
【问题描述】:
使用python3.4。在这里,我想使用 singledispatch 在 __mul__ 方法中调度不同的类型。像这样的代码:
class Vector(object):
## some code not paste
@functools.singledispatch
def __mul__(self, other):
raise NotImplementedError("can't mul these type")
@__mul__.register(int)
@__mul__.register(object) # Becasue can't use Vector , I have to use object
def _(self, other):
result = Vector(len(self)) # start with vector of zeros
for j in range(len(self)):
result[j] = self[j]*other
return result
@__mul__.register(Vector) # how can I use the self't type
@__mul__.register(object) #
def _(self, other):
pass # need impl
如你所见,我希望支持Vector*Vertor,这有名称错误
Traceback (most recent call last):
File "p_algorithms\vector.py", line 6, in <module>
class Vector(object):
File "p_algorithms\vector.py", line 84, in Vector
@__mul__.register(Vector) # how can I use the self't type
NameError: name 'Vector' is not defined
问题可能是如何在类的方法中使用类名类型?我知道 C++ 有字体类声明。 python如何解决我的问题?很奇怪看到result = Vector(len(self)) Vector 可以在方法体中使用。
之后看看http://lukasz.langa.pl/8/single-dispatch-generic-functions/ 我可以选择这种方式来实现:
import unittest
from functools import singledispatch
class Vector(object):
"""Represent a vector in a multidimensional space."""
def __init__(self, d):
self._coords = [0 for i in range(0, d)]
self.__init__mul__()
def __init__mul__(self):
__mul__registry = self.__mul__.registry
self.__mul__ = singledispatch(__mul__registry[object])
self.__mul__.register(int, self.mul_int)
self.__mul__.register(Vector, self.mul_Vector)
def __setitem__(self, key, value):
self._coords[key] = value
def __getitem__(self, item):
return self._coords[item]
def __len__(self):
return len(self._coords)
def __str__(self):
return str(self._coords)
@singledispatch
def __mul__(self, other):
print ("error type is ", type(other))
print (type(other))
raise NotImplementedError("can't mul these type")
def mul_int(self,other):
print ("other type is ", type(other))
result = Vector(len(self)) # start with vector of zeros
for j in range(len(self)):
result[j] = self[j]*other
return result
def mul_Vector(self, other):
print ("other type is ", type(other))
#result = Vector(len(self)) # start with vector of zeros
sum = 0
for i in range(0,len(self)):
sum += self._coords[i] * other._coords[i]
return sum
class TestCase(unittest.TestCase):
def test_singledispatch(self):
# the following demonstrates usage of a few methods
v = Vector(5) # construct five-dimensional <0, 0, 0, 0, 0>
for i in range(1,6):
v[i-1] = i
print(v.__mul__(3))
print(v.__mul__(v))
print(v*3)
if __name__ == "__main__":
unittest.main()
答案很奇怪:
other type is <class 'int'> [3, 6, 9, 12, 15] other type is <class '__main__.Vector'> 55 error type is <class 'int'> Traceback (most recent call last): File "p_algorithms\vector.py", line 164, in <module> print(v*3) File "C:\Python34\lib\functools.py", line 710, in wrapper return dispatch(args[0].__class__)(*args, **kw) File "p_algorithms\vector.py", line 111, in __mul__ raise NotImplementedError("can't mul these type")
v.__mul__(3) 可以工作,但v*3 不能工作。这很奇怪,从我的选项来看,v*3 与 v.__mul__(3) 相同。
@Martijn Pieters 发表评论后更新,我仍然想在课堂上实现v*3。所以我试试这个
import unittest
from functools import singledispatch
class Vector(object):
@staticmethod
def static_mul_int(self,other):
print ("other type is ", type(other))
result = Vector(len(self)) # start with vector of zeros
for j in range(len(self)):
result[j] = self[j]*other
return result
@singledispatch
@staticmethod
def __static_mul__(cls, other):
print ("error type is ", type(other))
print (type(other))
raise NotImplementedError("can't mul these type")
__mul__registry2 = __static_mul__.registry
__mul__ = singledispatch(__mul__registry2[object])
__mul__.register(int, static_mul_int)
def __init__(self, d):
self._coords = [0 for i in range(0, d)]
self.__init__mul__()
def __init__mul__(self):
__mul__registry = self.__mul__.registry
print ("__mul__registry",__mul__registry,__mul__registry[object])
self.__mul__ = singledispatch(__mul__registry[object])
self.__mul__.register(int, self.mul_int)
print ("at last __mul__registry",self.__mul__.registry)
# @singledispatch
# def __mul__(self, other):
# print ("error type is ", type(other))
# print (type(other))
# raise NotImplementedError("can't mul these type")
def mul_int(self,other):
print ("other type is ", type(other))
result = Vector(len(self)) # start with vector of zeros
for j in range(len(self)):
result[j] = self[j]*other
return result
def __setitem__(self, key, value):
self._coords[key] = value
def __getitem__(self, item):
return self._coords[item]
def __len__(self):
return len(self._coords)
def __str__(self):
return str(self._coords)
class TestCase(unittest.TestCase):
def test_singledispatch(self):
# the following demonstrates usage of a few methods
v = Vector(5) # construct five-dimensional <0, 0, 0, 0, 0>
for i in range(1,6):
v[i-1] = i
print(v.__mul__(3))
print("type(v).__mul__'s registry:",type(v).__mul__.registry)
type(v).__mul__(v, 3)
print(v*3)
if __name__ == "__main__":
unittest.main()
这一次。 v.__mul__(3) 有错误:
Traceback (most recent call last): File "test.py", line 73, in test_singledispatch type(v).__mul__(v, 3) File "/usr/lib/python3.4/functools.py", line 708, in wrapper return dispatch(args[0].__class__)(*args, **kw) TypeError: 'staticmethod' object is not callable
对我来说,静态方法应该像实例方法一样。
【问题讨论】:
-
v * 3与v.__mul__(3)不一样;它与type(v).__mul__(v, 3)相同。见Special method lookup。 -
我编码的v.__mul__(3),确实像__mul__(v,3),这里v是对象,3是我在·__init__mul__·中注册的类型(就像我绑定第二个这个有趣的 arg 发送)。如果 type(v).__mul__(v, 3) 不一样。与 v.__mul__(3) 有什么区别。在c语言级别?
-
了解 Python 函数充当描述符很重要;见From Function to Method和descriptor HOWTO;这就是 Python 如何绑定一个函数到一个实例,给你一个方法。
-
但是,对于特殊方法(所以
__mul__和__add__和__hash__等,以支持创建一个类和其他用例的哈希), Python 绕过绑定方法,而是手动传入self;type(v).__mul__(v, 3)接受未绑定的函数,将v直接作为self传入。 -
不清楚你为什么在你的赏金信息中问你的小问题;无论哪种方式,你都不能在方法上使用
functools.singledispatch,因为装饰器总是应用于未绑定函数,而不是方法,所以第一个参数是alwaysself。我的回答通过将方法委托给单独的外部 singledispatch 函数来回避这个问题。
标签: python class types python-3.4 dispatch