入场价格基于年龄

Question

我正在尝试开发一个程序，您可以在其中根据年龄计算入场费。价格为：14 岁及以下（5.00 美元）、15 至 64 岁（9.00 美元）和 65 岁及以上（7.50 美元）。客户也可能有一张优惠券，可以从他们的价格中扣除一美元。到目前为止，我想出了：

print ("Hello, welcome to Hopper's Computer Museum! To determine your enterance fee, please enter the following:")

print ('Your Date of Birth (mm dd yyyy)')
Date_of_Birth = input("--->")

print ('Todays Date: (mm dd yyyy)')
Todays_Date = input("--->")

age = (tYear-bYear)
if (bMonth > tMonth):
    age == age-1
if (bMonth == tMonth and
    bDay > tDay):
    age == age-1

price = -1
while price == -1:
    try:
        age = int(input('age:'))
    excpet ValueError:
        print("Not a number, try again.")
        continue
    if age <= 14:
        price==5.00
    elif age > 15 and age < 64:
        price==9.00
    else age > 65:
        price==7.50

print ('Do you have a coupon (y/n)?')
Discount = input("--->")
if Discount == "y" or Discount == "Y":
    price = price-1
elif Discount == "n" or Discount == "N":
    price = price

print ('Your admission fee is '+str(price)')

我感到困惑的一件事是如何让 Python 获取用户输入的日期并将其放入我设置的年龄计算中。

Answer 1

如果您想要一个固定的格式，用户将提供日期，例如 dd/mm/yyyy 或 mm/dd/yyyy

那么你可以简单地使用：

import datetime
date_time_object = datetime.datetime.strptime(date_provided, date_format)

#date_provided = '12/01/1995'
#date_format = '%d/%m/%Y'

curr_time = datetime.datetime.now()
time_diff = curr_time - date_time_object
print time_diff
age_days = time_diff.days
age_years = age_days / 326.25
print age_years 

Answer 2

您可以指定要采用的日期格式，然后将其拆分为 ...

import datetime
date_entry = input('Enter a date in YYYY-MM-DD format')
year, month, day = map(int, date_entry.split('-'))
date1 = datetime.date(year, month, day)

或者您可以参考以下链接了解更多信息...

getting-input-date-from-the-user-in-python-using-datetime-datetime

how-to-have-user-input-date-and-subtract-from-it

how-do-i-take-input-in-the-date-time-format