将 TypeScript 枚举合并为一个 [重复]

Question

为方便起见，我想合并两个单独的枚举。

export enum ActionTypes1 {
  ClearError = 'CLEAR_ERROR',
  PrependError = 'PREPEND_ERROR',
}

export enum ActionTypes2 {
  IncrementCounter = 'INCREMENT_COUNTER',
}

是否可以调用一个枚举来访问两者的数据？

例如

Foo.ClearError // works
Foo.IncrementCounter // works

对于上下文，我使用枚举作为函数名称。在这里用一个常量替换枚举：

// Error: A computed property name in a type literal must refer to an expression whose type is a literal type or a 'unique symbol' type.

async [ActionTypes.IncrementCounter]({ commit }) { 

Answer 1

您可以创建一个const 对象来完成相同的操作：

const Foo = {
  ...ActionTypes1,
  ...ActionTypes2
} as const;
type Foo = ActionTypes1 | ActionTypes2

const bar: ActionTypes1 = Foo.ClearError;
const baz: Foo = ActionTypes2.IncrementCounter;