cython / numpy 类型的数组

Question

我正在尝试构造一个 python 类型 int 的矩阵，一个 64 位有符号整数。

cdef matrix33():
    return np.zeros((3,3),dtype=int)

cdef do_stuf(np.ndarray[int, ndim=2] matrix):
    ...
    return some_value

def start():
    print do_stuf(matrix33())

它编译正确，但是当我运行它时，我不断收到此错误：

ValueError: Buffer dtype mismatch, expected 'int' but got 'long'

我无法使用 python long，但我不知道如何正确转换为 64 int。

更新

好的。我很确定我正确使用了 Cython。我写的代码是在抓包游戏/雅达利围棋中进行最小最大搜索。

到目前为止，调用次数最多的函数是：

cdef isThere_greedy_move(np.ndarray[np.int64_t, ndim=2]board, int player):
    cdef int i, j
    for i in xrange(len(board)):
        for j in xrange(len(board)):
            if board[i,j] == 0:
                board[i,j] = player
                if player in score(board):
                    board[i,j] = 0
                    return True
                board[i,j] = 0
    return False


# main function of the scoring system.
# returns list of players that eat a stone
cdef score(np.ndarray[np.int64_t, ndim=2] board):
    scores = []
    cdef int i,j
    cdef np.ndarray[np.int64_t, ndim = 2] checked
    checked = np.zeros((board.shape[0], board.shape[1]), dtype = int)
    for i in xrange(len(board)):
        for j in xrange(len(board)):
            if checked[i,j] == 0 and board[i,j] !=0:
                life, newly_checked = check_life(i,j,board,[])
                if not life:
                    if -board[i,j] not in scores:
                        scores.append(-board[i,j])
                        if len(scores) == 2:
                            return scores
                checked = update_checked(checked, newly_checked)
    return scores

# helper functions of score/1
cdef check_life(int i, int j, np.ndarray[np.int64_t, ndim=2] board, checked):
    checked.append((i,j))
    if liberty(i,j,board):
        return True, checked
    for pos in [[1,0],[0,1],[-1,0],[0,-1]]:
        pos = np.array([i,j]) + np.array(pos)
        if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == board[i,j] and (pos[0],pos[1]) not in checked:
            life, newly_checked = check_life(pos[0],pos[1],board,checked)
            if life:
                checked = checked + newly_checked             
                return life, checked
    return False, []    # [] is a dummy.

cdef liberty(int i,int j, np.ndarray[np.int64_t, ndim=2] board):
    for pos in [np.array([1,0]),np.array([0,1]),np.array([-1,0]),np.array([0,-1])]:
        pos = np.array([i,j]) - pos
        if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == 0:
            return True
    return False

我真的以为这将是一个让 cython 大放异彩的机会。 解决 3x3 捕获问题：

Python 2.7 执行一致的 2.28 秒，使用 cython 执行一致的 2.03 两者均使用 python 时间模块和低于 60C° 的 i7 处理器进行了测试

现在我的问题是我是否要为这个项目切换到 Haskell 或 C++...

Answer 1

Cython 的 int 类型与 C int 相同，即通常（但不一定）32 位。您应该将matrix33 中的dtype 声明为np.int64，并将do_stuf 中的np.int64_t 声明为C 对应项：

cimport numpy as np
import numpy as np

cdef do_stuff(np.ndarray[np.int64_t, ndim=2] matrix):
    pass

cdef matrix33():
    return np.zeros((3,3), dtype=int)

def start():
    print do_stuff(matrix33())