如何使用 while 循环从用户输入中附加任意数量的键和多个值的字典

Question

print('Scenario Analysis')

profit_dict = {}

while True:
    item1= input ('What is the item: ')   
    price_good= int (input('What is the expected profit of {}, in the best case scenario: '.format(item1)))
    price_bad = int( input ('What is the expected profit of {}, in the worst case scenario: '.format(item1)))
    user_choice= input('Do you have anymore items: ')
    if user_choice in ['Yes','yes','y','Y']:
            pass
    else:
            break

profit_dict[item1]=price_good,price_bad

#EVERYTHING FROM HERE ON IS NOT RELEVANT DIRECTLY TO QUESTION BUT PROVIDES CONTEXT

print('This is your best profit outcome: ')
for values in good_dict.values():
    total_list=(max(values))
    print(total_list)

print('This is your worst profit outcome: ')

我知道变量的使用会不断取代字典，但这是我展示我的目标的最佳方式。可能使用函数而不是 while 循环可能会有所帮助，但我不确定。

提前感谢您的任何回复。

Answer 1

这样的事情是否符合您的期望：

print('Scenario Analysis')

profit_dict = {}

while True:
   item1= input ('What is the item: ')
   price_good= int (input('What is the expected profit of {}, in the best case scenario: '.format(item1)))
   price_bad = int( input ('What is the expected profit of {}, in the worst case scenario: '.format(item1)))

   if item1 in profit_dict.keys():
       profit_dict[item1]['good'].append(price_good)
       profit_dict[item1]['bad'].append(price_bad)

   else:
       profit_dict[item1]={'good':[price_good],'bad':[price_bad]}

   user_choice= input('Do you have anymore items: ')
   if user_choice in ['Yes','yes','y','Y']:
        pass
   else:
        break

=> 你会得到一个字典的字典： {'Item1':{'good':[1,2,3],'bad':[0,0,1]},'Item2':{'good':[10,20,30],'bad ':[1,2,3]}, ,...,'ItemX':{'good':[10,20,30], 'bad':[1,2,3]}}

然后您可以尝试使用以下内容调用打印：

print(f'This is your best profit outcome: {max(profit_dict[item]['good'])}')
print(f'This is your worst profit outcome: {min(profit_dict[item]['bad'])}')

编辑： 不确定是否理解您的评论： 如果您正在寻找特定项目：

item='item1'
print(f'This is your best profit outcome: {max(profit_dict[item]['good'])}')

如果项目未知 您可以通过迭代探索字典：

for key, value in profit_dict.items():
    for key2, value2 in value.items():
        print(f"This is your best profit outcome for {key}:{max(profit_dict[item]['good'])}")

它会打印你： 这是您对 Item1:3 的最佳利润结果 这是您对 Item2:30 的最佳利润结果 ... 这是 ItemX 的最佳利润结果：30

如果你想知道“好”更大的项目，这个解决方案不是最好的，但你仍然可以进行迭代：

previous_best_value=0
for key, value in profit_dict.items():
    for key2, value2 in value.items():
        best_value=max(profit_dict[key]['good'])
        if best_value>previous_best_value:
            previous_best_value=best_value
            best_item=key

print(f"The item:{key} has the best outcome {previous_best_value}")

希望你会找到你所期望的。

Answer 2

profit_dict = {}

while True:
    item1= input ('What is the item: ')   
    price_good= int (input('What is the expected profit of {}, in the best case scenario: '.format(item1)))
    price_bad = int( input ('What is the expected profit of {}, in the worst case scenario: '.format(item1)))
    user_choice= input('Do you have anymore items: ')
    profit_dict[item1]=[price_good,price_bad]    
    if user_choice in ['Yes','yes','y','Y']:
            continue
    else:
            break

print(profit_dict)

这就是你要找的吗？这只是继续添加字典，直到用户输入是。