如何仅输出列表数据中的字符串？

Question

我的文件读取的是 teamNames.txt 文件：

Collingwood

Essendon

Hawthorn

Richmond

代码：

file2 = input("Enter the team-names file: ") ## E.g. teamNames.txt

bob = open(file2)
teamname = []

for line1 in bob: ##loop statement until no more line in file
    teamname.append(line1)

print(teamname)

输出是：

['Collingwood\n', 'Essendon\n', 'Hawthorn\n', 'Richmond\n']

我想这样做，所以输出将是：

Collingwood, Essendon, Hawthorn, Richmond

Answer 1

怎么样

for line1 in bob:
    teamname.append(line1.strip()) # .strip() removes the \n

print (', '.join(teamname))

.join() 进行最终格式化。

---

更新。我现在认为一个更蟒蛇（和优雅）的答案是：

file2 = input("Enter the team-names file: ") ## E.g. teamNames.txt

with open(file2) as f:
    teamname = [line.strip() for line in f]

print (', '.join(teamname))

with 语句确保文件在块完成时关闭。它不再使用for 循环，而是使用list comprehension，这是一种很酷的方法，通过转换另一个列表（或iterable object，如file）中的元素来创建列表。

Answer 2

join 方法效果很好，但您也可以尝试使用 for 循环。

for name in teamname: # takes each entry separately 
    print name

Answer 3

一种选择是使用replace() 函数。我已修改您的代码以包含此功能。

file2= input("Enter the team-names file: ") ## E.g. teamNames.txt

bob =open(file2)
teamname = []

for line1 in bob: ##loop statement until no more line in file
    teamname.append(line1.replace("\n",""))

print(teamname)

会给你输出：

['Collingwood', 'Essendon', 'Hawthorn', 'Richmond']

然后您可以修改teamname 以获得您请求的输出：

print(", ".join(teamname))