MYSQL Brands 按产品数量列出订单，但

Question

我有两张桌子。像这样；

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Products table

id | brand | bla bla bla

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Priority table

id | brand

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我正在列出从 Products 表中选择 DISTINCT 品牌 BY ORDERING product COUNT like this;

SELECT DISTINCT brand as bra, (SELECT COUNT(id) FROM Products WHERE brand = bra) as cnt FROM Products ORDER BY cnt DESC

结果是：

1. 一个品牌（65 种产品）
2. B 品牌（43 种产品）
3. C 品牌（23 种产品）
4. D 品牌（17 种产品）

这是一条完美的工作线。但我想优先考虑一些品牌。用于列表顶部。

像这样：

1. S 品牌（22 种产品）
2. X 品牌（4 个产品）
3. 一个品牌（65 种产品）
4. B 品牌（43 种产品）
5. C 品牌（23 种产品）
6. D 品牌（17 种产品）

我使用了这条线。但它没有用。

SELECT DISTINCT brand as bra, (SELECT COUNT(id) FROM Products WHERE brand = bra) as cnt, , (SELECT brand FROM Priority) as prior FROM Products ORDER BY prior ASC,cnt DESC

什么是真线？谢谢...

---编辑--- 完整答案是：

SELECT p.brand as bra, count(p.id) as cnt
FROM products p
GROUP BY bra
ORDER BY bra IN (SELECT pri.brand FROM priority pri ORDER BY pri.brand ASC) DESC, mark ASC

Answer 1

使用这个：

ORDER BY bra IN (SELECT brand FROM Priority) DESC, cnt DESC

Answer 2

您的第一个查询更清楚地写成：

SELECT b.brand as bra, count(p.id) as cnt
FROM bra b left outer join
     Products p
     on b.brand = p.brand
GROUP BY b.bra
ORDER BY cnt DESC;

只有在您担心不匹配的记录时才需要left outer join。如果这不是问题，编写查询的更简单方法是：

SELECT p.brand as bra, count(p.id) as cnt
FROM Products p
GROUP BY p.bra
ORDER BY cnt DESC;

如果您想按优先级排序，只需加入即可。这可能就是您想要的：

SELECT p.brand as bra, count(p.id) as cnt
FROM bra b left outer join
     Products p
     on b.brand = p.brand left outer join
     Priority pr
     on b.brand = pr.brand
GROUP BY b.bra
ORDER BY pr.brand is not null desc, cnt DESC;

这会将品牌放在优先级表中。