【发布时间】:2016-12-31 12:00:54
【问题描述】:
我有一个类似的查询
SELECT COUNT(ShoppingProductFeature.ShoppingFeatureId) as countShow,ShoppingProductFeature.ShoppingFeatureId as valueId, ShoppingProductFeature.ShoppingParentFeatureId as attrId, ShoppingFeatureLanguage.Title as attrName, ShoppingFeatureLanguage_1.Title AS valueName
FROM ShoppingFeatureLanguage INNER JOIN ShoppingProductFeature INNER JOIN ShoppingFeatureLanguage AS ShoppingFeatureLanguage_1 ON ShoppingProductFeature.ShoppingFeatureId = ShoppingFeatureLanguage_1.ShoppingFeatureId ON ShoppingFeatureLanguage.ShoppingFeatureId = ShoppingProductFeature.ShoppingParentFeatureId INNER JOIN ShoppingFeature ON ShoppingProductFeature.ShoppingFeatureId = ShoppingFeature.ShoppingFeatureId
INNER JOIN Product ON ShoppingProductFeature.ProductId = Product.ProductId
INNER JOIN Company ON Product.CompanyId = Company.CompanyId
GROUP BY ShoppingProductFeature.ShoppingFeatureId, ShoppingProductFeature.ShoppingParentFeatureId, ShoppingFeatureLanguage.Title, ShoppingFeatureLanguage_1.Title, ShoppingFeatureLanguage_1.LanguageId, ShoppingFeatureLanguage.LanguageId, ShoppingFeature.isConfirmed,Product.MoneyId,Product.TypeId , Company.GeoId , Product.ShoppinGroupId
HAVING (ShoppingFeatureLanguage_1.LanguageId = 2) AND (ShoppingFeatureLanguage.LanguageId = 2) AND (ShoppingFeature.isConfirmed = 1) and (Product.TypeId = 11) and Product.ShoppinGroupId like N'mn%' and Company.GeoId like N'aa%'
ORDER BY countShow DESC
很明显,我必须按 countShow 对其进行排序,并且我必须调用 COUNT(ShoppingProductFeature.ShoppingFeatureId) 进行选择,因为我无法将其添加到 Order By
所以结果是这样的 enter image description here
如何区分数据或在没有重复数据的情况下对它们进行排序
【问题讨论】:
-
你为什么使用
HAVING没有GROUP BY子句?您的查询是否会运行? -
抱歉我删了,我要编辑帖子
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您问了一个错误的问题,因为您的查询不可读/不可用,并且您使用了当前结果的链接。话虽如此,我在您当前的输出中看不到任何“重复”。如果你想把它变成一条记录,改变分组和聚合。
标签: sql select count sql-order-by distinct