MYSQL 逗号分隔的选择结果答案

【问题标题】：MYSQL comma base separated select resultMYSQL 逗号分隔的选择结果
【发布时间】：2016-04-02 07:20:40
【问题描述】：

我有 4 张桌子，如下所示。

表：类

ClassID     |   ClassSTD
--------------------------------
1           |   STD-1<br>
2           |   STD-2

表格：部分

SectionId   |   SectionName | ClassId
--------------------------------------------
1           |   sec-A       | 1
2           |   sec-B       | 1
3           |   sec-C       | 1
4           |   sec-A       | 2
5           |   sec-B       | 2
6           |   sec-C       | 2

表格：主题

subjectId   |   subjectName
------------------------------------
1           |   Art
2           |   Music
3           |   Play

表SubjectAllocationToClass

    classId         |   sectionID           |   subjectId   | type
-----------------------------------------------------------------------
1(STD-1)        |   1(sec-A)            |   1(Art)      | main
1(STD-1)        |   2(sec-B)            |   1(Art)      | main
1(STD-1)        |   3(sec-C)            |   1(Art)      | optional
1(STD-1)        |   1(sec-A)            |   2(Music)    | main
1(STD-1)        |   2(sec-B)            |   2(Music)    | optional

上表“SubjectAllocationToClass”显示了两种类型的主题（主要和可选）到班级部分的分布。如何从 SELECT 语句中获得以下结果？

classSTD |  sectionName | Main subjectName   | Optional subjectName
-----------------------------------------------------------------------------
STD-1    |  sec-A       | Art, Music         |
STD-1    |  sec-B       | Art                |  Music
STD-1    |  sec-C       |                    |  Art

【问题讨论】：

是的，这是可能的，它被称为GROUP_CONCAT agg 函数。问题是到目前为止您尝试了什么？

标签： mysql sql select group-by group-concat

【解决方案1】：

使用GROUP_CONCAT()函数：

试试这个：

SELECT D.classSTD, 
       C.sectionName, 
       GROUP_CONCAT(B.subjectName SEPARATOR ', ') AS subjectName
FROM SubjectAllocationToClass A 
INNER JOIN Subject B ON A.subjectId = B.SubjectId 
INNER JOIN Section C ON A.sectionId = C.SectionId   
INNER JOIN Class D ON A.classID = D.ClassID 
GROUP BY D.ClassID, C.SectionId;

关于您的另一个问题

SELECT D.classSTD, 
       C.sectionName, 
       GROUP_CONCAT(B.subjectName SEPARATOR ', ') AS subjectName, 
       GROUP_CONCAT(CASE WHEN B.type = 'main' THEN B.subjectName ELSE NULL END SEPARATOR ', ') AS mainsubjectName, 
       GROUP_CONCAT(CASE WHEN B.type = 'optional' THEN B.subjectName ELSE NULL END SEPARATOR ', ') AS optionalSubjectName
FROM SubjectAllocationToClass A 
INNER JOIN SUBJECT B ON A.subjectId = B.SubjectId 
INNER JOIN Section C ON A.sectionId = C.SectionId   
INNER JOIN Class D ON A.classID = D.ClassID 
GROUP BY D.ClassID, C.SectionId;

【讨论】：

为什么要投反对票？给出原因，以便其他人可以在我的查询中找到问题？？？
你能帮帮我吗，我在主要描述中编辑了条件

【解决方案2】：

您可以通过group_concat 执行此操作，如下所示：

select classSTD , SectionName ,  group_concat(`subjectName` separator ',') as `subjectName` 
FROM SubjectAllocationToClass 
INNER JOIN Class ON SubjectAllocationToClass.classId = Class.ClassID 
INNER JOIN Section ON SubjectAllocationToClass.sectionID   = Section.sectionId
INNER JOIN Subject ON SubjectAllocationToClass.subjectID   = Subject .subjectId  
GROUP BY  SubjectAllocationToClass.subjectID ;

【讨论】：

【解决方案3】：

使用GROUP_CONCAT

 SELECT  sec.SectionName , cl.classSTD, GROUP_CONCAT(`sub.subjectName`) as `subjectName` FROM SubjectAllocationToClass AS al JOIN Class AS cl ON al.classId = cl.ClassID JOIN Section AS sec ON al.sectionID  = sec.sectionId JOIN Subject AS sub ON al.subjectID   = sub.subjectId  
GROUP BY  al.subjectID;

【讨论】：