根据现有表数据插入新行 (SQL Server 2008 R2)

Question

现在我有两张桌子，

Table A:

  number  date       name
  -------------------------
  a1101   20141209   jim
  a1101   20141210   jim
  a1101   20141211   jim
  a1102   20141209   andy

Table B:

  number  date       
  -------------------
  a1101   20141209   
  a1101   20141210   
  a1101   20141211 
  a1101   20141212

如你所见，当number = a1101，日期"20141212"在table A中不存在，当满足这个条件时，我需要向table A插入数据：

 number  date       name
 a1101   20141212   jim

我不知道这个sql怎么写，期待你的帮助。

添加：

当我表演时：MERGE tableA As Target USING (Select b.number, b.date, a.name From tableB b Left Join tableA a ON a.number = b.number )AS Source ON Source.number = Target.number AND
Source.date = Target.date WHEN NOT MATCHED THEN INSERT (number, date, name) VALUES (source.number, source.date, source.name); 插入三个相同的数据：

a1101   20141212  jim
a1101   20141212  jim
a1101   20141212  jim

Answer 1

您可以使用 INSERT...SELECT 语句。

试试这个：

INSERT INTO tableA (number, date, name)
SELECT b.number, b.date, c.name
FROM tableB AS b 
INNER JOIN (SELECT a.number, MAX(a.name) AS name FROM tableA a GROUP BY a.number) AS c ON a.number = c.number 
LEFT OUTER JOIN tableA AS a ON b.number = a.number AND b.date = a.date 
WHERE a.number IS NULL;

Answer 2

你可以像这样使用SQLMerge进行条件插入，

MERGE TableA As Target
USING (Select b.number, b.date, a.name From TableB b Left Join TableA a ON a.number = b.number  )AS Source
ON Source.number  = Target.number  AND       
 Source.date = Target.date
WHEN NOT MATCHED THEN
 INSERT (number, date, name)
    VALUES (source.number, source.date, source.name)

Answer 3

INSERT INTO #TableA
SELECT DISTINCT a.Number,
       a.[date],
       b.name
FROM   #TableB A
INNER JOIN   #TableA B ON A.NUMBER = B.NUMBER              
WHERE  A.DATE NOT IN (SELECT [date]
                      FROM   #TableA)